Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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The simplest way to start thinking about an array is as a collection, or a set of elements. In programming, these elements may be constants, variables, functions and pointers.
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Assume class ArrayStack has been defined using the implementation in your textbook and that myStack has been initialized so it is empty. Type the EXACT output of the following code segment. You may assume that the code compiles and executes without errors. ```cpp ArrayStack<int> myStack; int i = 1; int j = 2; int k = 3; int n = 4; myStack.push(j); myStack.push(k); i = myStack.peek(); myStack.pop(); myStack.push(n); k = myStack.peek(); myStack.pop(); myStack.push(n); myStack.push(i); myStack.push(k); while (!myStack.isEmpty()) { i = myStack.peek(); myStack.pop(); cout << i << " "; } cout << endl; ``` ### Explanation 1. **Initialization**: The stack `myStack` is initialized and integers `i`, `j`, `k`, and `n` are assigned values 1, 2, 3, and 4, respectively. 2. **Stack Operations**: - Push `j` (2) onto the stack. - Push `k` (3) onto the stack. - Peek the top of the stack (3), assign it to `i`, then pop. - Push `n` (4). - Peek the top of the stack (4), assign it to `k`, then pop. - Push `n` (4). - Push `i` (3). - Push `k` (4). 3. **While Loop**: Continuously peeks the top of the stack, assigns it to `i`, pops the stack, and prints `i` until the stack is empty. Finally, a newline is printed. ### Output The output will be the sequence in which the integers are popped and printed, reflecting the stack operations: ``` 4 3 4 2 ```
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Transcribed Image Text:Assume class ArrayStack has been defined using the implementation in your textbook and that myStack has been initialized so it is empty. Type the EXACT output of the following code segment. You may assume that the code compiles and executes without errors. ```cpp ArrayStack<int> myStack; int i = 1; int j = 2; int k = 3; int n = 4; myStack.push(j); myStack.push(k); i = myStack.peek(); myStack.pop(); myStack.push(n); k = myStack.peek(); myStack.pop(); myStack.push(n); myStack.push(i); myStack.push(k); while (!myStack.isEmpty()) { i = myStack.peek(); myStack.pop(); cout << i << " "; } cout << endl; ``` ### Explanation 1. **Initialization**: The stack `myStack` is initialized and integers `i`, `j`, `k`, and `n` are assigned values 1, 2, 3, and 4, respectively. 2. **Stack Operations**: - Push `j` (2) onto the stack. - Push `k` (3) onto the stack. - Peek the top of the stack (3), assign it to `i`, then pop. - Push `n` (4). - Peek the top of the stack (4), assign it to `k`, then pop. - Push `n` (4). - Push `i` (3). - Push `k` (4). 3. **While Loop**: Continuously peeks the top of the stack, assigns it to `i`, pops the stack, and prints `i` until the stack is empty. Finally, a newline is printed. ### Output The output will be the sequence in which the integers are popped and printed, reflecting the stack operations: ``` 4 3 4 2 ```
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