Assume th at we have a computer with a cache memory of 512 blocks with a total size of 128K bits. Knowing thatthe computer uses a word addressable mode and the format of the memory address as seen by the Fully associative cache scheme is as shown below, an swer the pelow question s: Fully Associative Cache Format 19 1- How many words do we have in each cache block? 2- What is the size of each word? 3- What is the size of the main memory? 4- How many blocks are there in the main memory? 5- Draw the format of the memory address as seen by the Direct Mapped Cache scheme, showing the fields as well as their sizes.

Suppose we have a byte-addressable computer with a cache that holds 8 blocks of 16 bytes each.  Assuming that each memory address has 16 bits, to which cache block would the hexadecimal address 0x13F map if the computer uses direct mapping? Blocks are numbered starting at 0.

Take into account the following scenario: we have a byte-addressable computer with 2-way set associative mapping, 16-bit main memory addresses, and 32 blocks of cache memory. Since there are 8 bytes in a block, you can use that information to calculate how big the offset field has to be.

3. Caching In this question, let's assume that we have a 16-bit system with a single level 6-way set associative cache with 8 sets, and a cache block size of 64 bytes. How many bits are needed for the setID and the tags? Draw the breakdown of the tag/index/byte- in-block bits. What is the total size of this cache? For the following program, assume that an integer is 4 bytes. int i; // Assume these variables are stored in the registers. int a[65536]; // Assume that a = 0x1000 int b[65536]; // Assume that b = 0x8000000 for (i=0; i<1024; i++) a[i* 8 ] = i; for (i=0; i<1024; i++) b[i * 8 ] = a[i * 8 ]++; Let's asssume that the array is initialized to zero and that the variable i is already stored on the register. What is my cache hit rate? Show your work.

Assume a cache of 1 MB organized as 32 bytes each line. The main memory is 256 MB. a. Determine the number of blocks in main memory b. Determine how to split the address (s-r, r, w) for direct mapping. c. Determine how to split the address (s, w) for associative mapping. d. Determine how to split the address (s-d, d, w) for set-associative each cache set is 4 lines of the cache.

Suppose we have a byte-addressable computer with a cache that holds 16 blocks of 4 bytes address has 8 bits, to which cache set would the hexadecimal address OxBE map if the computer mapping? each. Assuming that each memory uses 2-way set associative

Consider a 64K L2 memory and a 4K L1 2-way associative cache with block sizes of 512. a. How many blocks are in each set in L1? b. How many offset bits are in the L2 address? c. How many index bits are in the L2 address? d. How many tag bits are in the L2 address?

Take into account the following scenario: we have a byte-addressable computer with 2-way set associative mapping, 16-bit main memory addresses, and 32 blocks of cache memory. Since there are 8 bytes in a block, you can use that information to calculate how big the offset field has to be.

Question 24 Some portion of cache system B represented a 2-way set-associative mapping cache system. The system is byte-addressable and the block size is one word (4 bytes). The tag and set number are represented with a binary numbers. The contents of words in the block are represented with hexadecimal. Tag 10 1000 0100 1001 11 1100 0100 1001 10 1000 0100 1001 11 1100 0100 1101 10 1000 0100 1001 11 1100 0100 1001 10 1000 0100 1001 11 1100 0100 1101 10 1000 0100 1001 11 1100 0100 1001 10 1000 0100 1001 11 1100 0100 1101 Set Number 0110 1101 0110 1101 0110 1110 0110 1110 0110 1111 0110 1111 0111 0000 0111 0000 0111 0001 0111 0001 0111 0010 0111 0010 00 2. What is the size of cache memory? Word within block 01 2016 6116 C116 10 3216 7216 C216 4216 8216 4116 5216 9216 8216 3216 4216 8216 6116 1. What is the size of the main memory for cache system B? 11 2116 D216 2016 6116 D116 3216 7216 C216 D216 A216 B216 5116 5216 A216 5216 2716 6116 C116 7216 C216 A216 8216 4116 A216 5216 9216 5216…