At the end of the experiment, it was discovered that the thermometer had not been calibrated. When it was calibrated, it was found that the thermometer read 0.50 C low. What effect would thus thermometer reading have on the reported change in H neoutzn calculated above?

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Chapter15: Acid-base Equilibria
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At the end of the experiment, it was discovered that the thermometer had not been calibrated. When it was calibrated, it was found that the thermometer read 0.50 C low. What effect would thus thermometer reading have on the reported change in H neoutzn calculated above?
© 1988 Cengage Learning
oriw olemholso odt ot quo otonorli rol 1esod eenlg 6 gntutedue to gilidig oieno.E
alubom eirli ni becioeob inomiopo srit anob
2. When a neutralization reaction was carried out using 100.0 mL of 0.7890M NH3 water and 100.0 mL of
0.7940M acetic acid, AT was found to be 4.76 °C. The specific heat of the reaction mixture was 4.104 J
gK and its density was 1.03 g mL-1. The calorimeter constant was 3.36 J K-1.
(1) Calculate AHneutzn for the reaction of NH3 and acetic acid.
heat absorbed. by reaction= (volume)( density) (AT) (specific hcat)
= (200 mL)(1.03)(4.76) (4.104)
= 4,0 24. 22
heat absor bed by calorimeter =kalorimet er constant)(AT)
= 3.36 (4.76) =15. 99
total heat = (heat absorbed by mixture) (heat absor bed bu cealorimeter) W (S)
= 4. 04 E 3J 4,04 WJ
1o bisoter
limiting Moks of NHs=0.789..130.0789 mol
agent
AH
ntu ten
6L/2 KJ /mol
.0774
Moles of CHg COOH=.794-. =,0794 m
answer
(2) At the end of the experiment, it was discovered that the thermometer had not been calibrated.
When it was calibrated, it was found that the thermometer read 0.50 °C low. What effect would
this thermometer reading have on the reported AHneutzn calculated in (2) above?
Transcribed Image Text:© 1988 Cengage Learning oriw olemholso odt ot quo otonorli rol 1esod eenlg 6 gntutedue to gilidig oieno.E alubom eirli ni becioeob inomiopo srit anob 2. When a neutralization reaction was carried out using 100.0 mL of 0.7890M NH3 water and 100.0 mL of 0.7940M acetic acid, AT was found to be 4.76 °C. The specific heat of the reaction mixture was 4.104 J gK and its density was 1.03 g mL-1. The calorimeter constant was 3.36 J K-1. (1) Calculate AHneutzn for the reaction of NH3 and acetic acid. heat absorbed. by reaction= (volume)( density) (AT) (specific hcat) = (200 mL)(1.03)(4.76) (4.104) = 4,0 24. 22 heat absor bed by calorimeter =kalorimet er constant)(AT) = 3.36 (4.76) =15. 99 total heat = (heat absorbed by mixture) (heat absor bed bu cealorimeter) W (S) = 4. 04 E 3J 4,04 WJ 1o bisoter limiting Moks of NHs=0.789..130.0789 mol agent AH ntu ten 6L/2 KJ /mol .0774 Moles of CHg COOH=.794-. =,0794 m answer (2) At the end of the experiment, it was discovered that the thermometer had not been calibrated. When it was calibrated, it was found that the thermometer read 0.50 °C low. What effect would this thermometer reading have on the reported AHneutzn calculated in (2) above?
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