(b) Find P(-1.77 < z < 2.03). (c) Find P(z < -1.4). (d) Find P(z < -0.42).

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter1: Basic Concepts And Properties
Section1.CR: Review Problem Set
Problem 66CR
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Consider the following. (Give your answers correct to four decimal places.)

(a) Find P(-2.06 < z < 0.00).


(b) Find P(-1.77 < z < 2.03).


(c) Find P(z < -1.4).


(d) Find P(z < -0.42).
 
 
Expert Solution
Step 1:

The standard normal distribution is a normal distribution with a mean of zero and a standard deviation of 1.

It is required to find the probabilities from the z-score.

z ~ N(mean = 0. standard deviation = 1)

Step 2: a)

 P(-2.06 < z < 0.00). 

The probability can be calculated as

P(-2.06 < z < 0.00) = P(z < 0) - P(z < -2.06)

P(-2.06 < z < 0.00) =  0.5 - 0.019699                     Using MS-Excel command NORM.S.DIST(0.5,TRUE) - NORM.S.DIST(-2.06,TRUE)

P(-2.06 < z < 0.00) = 0.48030

Step 3

(b) Find P(-1.77 < z < 2.03).

The probability can be calculated as

P(-1.77 < z < 2.03) = P(z < 2.03) - P(z < -1.77)

P(-1.77 < z < 2.03)= 0.978822 -  0.038364                   Using MS-Excel command NORM.S.DIST( 2.03,TRUE) -                                                                                                                                                     NORM.S.DIST(-1.77,TRUE)

P(-1.77 < z < 2.03) = 0.940458

Rounding to four decimal

P(-1.77 < z < 2.03) = 0.94046

 

                 

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