I need help answering PART B. a Escherichia coli cells are about 1.95 µm long and 0.595 µm in diameter.i) How many E. coli cells laid end to end would fit across a pinhead of diameter 0.5 mm?Number of cells = 256cellsii) Calculate the volume of an E. coli cell, assuming the cell to be cylindrical in shape.The volume of a cylinder is:Volume = ar²hCell volume = 0.542198x10 / m³iii) Calculate the surface area and surface area to volume ratio of an E. coli cell.The surface area of a cylinder is:Surface area = 2arh + 2rr²Surface area = 4.2011x10^- / m²Surface area:Volume = 7.75x10^6 b Glucose, a major energy-yielding nutrient, is present in bacterial cells at a concentration of approximately 0.300 mM.i) What is the concentration of glucose in the E. coli cell in mg/mL?| mg/mLConcentration =|ii) Calculate the number of glucose molecules present in a typical E. coli cell.(Avogadro's number = 6.023×1023 molecules mol"l)Number of glucose molecules =|molecules

b Glucose, a major energy-yielding nutrient, is present in bacterial cells at a concentration of approximately 0.300 mM. i) What is the concentration of glucose in the E. coli cell in mg/mL? Concentration = | |mg/mL ii) Calculate the number of glucose molecules present in a typical E. coli cell. (Avogadro's number = 6.023×1023 molecules mol"') Number of glucose molecules = ]molecules

b Glucose, a major energy-yielding nutrient, is present in bacterial cells at a concentration of approximately 0.300 mM. i) What is the concentration of glucose in the E. coli cell in mg/mL? Concentration = | |mg/mL ii) Calculate the number of glucose molecules present in a typical E. coli cell. (Avogadro's number = 6.023×1023 molecules mol"') Number of glucose molecules = ]molecules

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter1: Basic Concepts Of Chemistry

Section: Chapter Questions

Problem 43GQ: Hexane (C6H14, density = 0.766 g/cm3), perfluoro-hexane (C6F14, density = 1.669 g/cm3), and water...

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Use this video to answer the questions: https://www.youtube.com/watch?v=BocfSXdbaU0