Identify each compound from its molecular formula and its 1H NMR spectrum: C9H12 b. CH100106.48(ppm)frequency

Answered: b. CH100 10 6. 4 8(ppm) frequency

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Identify each compound from its molecular formula and its ¹H NMR spectrum: C₉H₁₂

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Step 1

The double bond equivalent for the compound is equal to 1. This suggests the presence of carbonyl group. The 10 hydrogens are divided into two sets, one set consists of six hydrogens and other consists of 4 H. Chemical shift at 1.0 ppm with triplet splitting indicates the presence of methyl group. Chemical shift at 2.4 ppm with quadrate splitting indicates the presence of methylene group. The higher increment of methylene group (base peak at 1.2 ppm) is due to the presence of carbonyl group.

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