Balanced chemical equation for neutralization of acid with NaOH Saved X1 Xi 1ITI金 1 Te Normal BIIU 而一而一中 H3A + 3NAOH -Na3A+ 3H20 Table view List view Table 5. Calculations for concentration of acid solution Sample 1 Sample 2 Sample 3 [1] Volume of acid (mL) 25.0 25.0 25.0 [2] Burette reading of NaOH, initial (mL) 1.67 2.68 4.05 [3] Burette reading of NaOH, final (mL) 27.88 28.84 30.00 [4] Volume of NaOH, dispensed (mL) 26.21 26.16 25.95 [5] Molar concentration of NaOH (part A) 0.1077 [6] Molar concentration of acid solution (M)

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter11: Solutions
Section: Chapter Questions
Problem 26P
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I need help with this problem please. The unknown acid type is H3A

Balanced chemical equation for neutralization of acid with Na0H
Saved
Ix
Xa1 X1
三一而一中
a181回10 田戸171 倒1 三1l
Normal
BIIU
H3A + 3NAOH -Na3A + 3H20
Table view
List view
Table 5. Calculations for concentration of acid solution
Sample 1
Sample 2
Sample 3
25.0
25.0
25.0
[1] Volume of acid (mL)
[2] Burette reading of
NaOH, initial (mL)
1.67
2.68
4.05
[3] Burette reading of
NaOH, final (mL)
27.88
28.84
30.00
[4] Volume of NaOH,
dispensed (mL)
26.21
26.16
25.95
[5] Molar concentration
of NaOH (part A)
0.1077
[6] Molar concentration
of acid solution (M)
Transcribed Image Text:Balanced chemical equation for neutralization of acid with Na0H Saved Ix Xa1 X1 三一而一中 a181回10 田戸171 倒1 三1l Normal BIIU H3A + 3NAOH -Na3A + 3H20 Table view List view Table 5. Calculations for concentration of acid solution Sample 1 Sample 2 Sample 3 25.0 25.0 25.0 [1] Volume of acid (mL) [2] Burette reading of NaOH, initial (mL) 1.67 2.68 4.05 [3] Burette reading of NaOH, final (mL) 27.88 28.84 30.00 [4] Volume of NaOH, dispensed (mL) 26.21 26.16 25.95 [5] Molar concentration of NaOH (part A) 0.1077 [6] Molar concentration of acid solution (M)
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