   # One half liter (500. mL) of 2.50 M HCl is mixed with 250. mL of 3.75 M HCl. Assuming the total solution volume after mixing is 750. mL, what is the concentration of hydrochloric acid in the resulting solution? What is its pH? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 111GQ
Textbook Problem
19 views

## One half liter (500. mL) of 2.50 M HCl is mixed with 250. mL of 3.75 M HCl. Assuming the total solution volume after mixing is 750. mL, what is the concentration of hydrochloric acid in the resulting solution? What is its pH?

Interpretation Introduction

Interpretation:

pH and concentration of HCl solution formed by mixing of two HCl solutions of different concentrations has to be determined.

Concept introduction:

• Strong acids dissociates completely into ions in solution but weak acids do not.
• pH of a solution is the negative of the base -10 logarithm of the hydronium ion concentration.

pH=-log[H3O+]

• Concentration of hydronium ion [H3O+]=10-pH
• Amountofsubstance=Concnetrationofthesubstance×Volume
• Concnetrationofthesubstance=AmountofsubstanceVolume
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
•  For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.

### Explanation of Solution

Here one half liter of 2.50MHCl is mixed with 250.0mLof3.75MHCl.  Total volume of the solution after mixing is 750mL.

The concentration of the resulting solution can be determined by calculating the amount of HCl in two different concentrations given.

From the concentration of HCl and its volume amount of HCl calculated as follows,

AmountofHCl=ConcnetrationHCl×VolumeHCl

Amount of HCl in one half liter of 2.50MHCl is,

2.50molL×0.5L=1.25molHCl

Amount of HCl in 250.0mLof3.75MHCl is,

3.75molL×0.25L=0.9375molHCl

Amount of HCl in 750.0mL solution is,

0.9375molHCl+1

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts
Energy-yielding nutrients include all of the following except. a. vitamins b. carbohydrates c. fat d. protein

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

Problem 18-3 Complete these Fischer esterification reactions:

Introduction to General, Organic and Biochemistry

Why is the Moon red during a total lunar eclipse?

Horizons: Exploring the Universe (MindTap Course List)

In 1801, Humphry Davy rubbed together pieces of ice inside an icehouse. He made sure that nothing in the enviro...

Physics for Scientists and Engineers, Technology Update (No access codes included)

Why do you think ridley turtles nest in such large numbers on the same beach?

Oceanography: An Invitation To Marine Science, Loose-leaf Versin 