BASED ON THE CASE SCENARIO, ANSWER QUESTION 55-60 In the leg ulcer trial, 233 patients with venous leg ulcers were randomly assigned to intervention group using a new regime treatment (Group 1) or the control group using the standard care (Group 2). Patients were treated and followed up for 3 months. The researcher would like to determine if there is any association between types of treatment for leg ulcer and ulcer status (healed or not healed) at 3 months. Which statistical method is appropriate for the above case? 1. Pearson’s correlation 2. Chi square goodness of fit test 3. Simple linear regression 4. Chi square test for independence
BASED ON THE CASE SCENARIO, ANSWER QUESTION 55-60 In the leg ulcer trial, 233 patients with venous leg ulcers were randomly assigned to intervention group using a new regime treatment (Group 1) or the control group using the standard care (Group 2). Patients were treated and followed up for 3 months. The researcher would like to determine if there is any association between types of treatment for leg ulcer and ulcer status (healed or not healed) at 3 months. Which statistical method is appropriate for the above case? 1. Pearson’s correlation 2. Chi square goodness of fit test 3. Simple linear regression 4. Chi square test for independence
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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BASED ON THE CASE SCENARIO, ANSWER QUESTION 55-60
In the leg ulcer trial, 233 patients with venous leg ulcers were randomly assigned to intervention group using a new regime treatment (Group 1) or the control group using the standard care (Group 2). Patients were treated and followed up for 3 months.
The researcher would like to determine if there is any association between types of treatment for leg ulcer and ulcer status (healed or not healed) at 3 months.
Which statistical method is appropriate for the above case?
1. Pearson’s
2. Chi square goodness of fit test
3. Simple linear regression
4. Chi square test for independence
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