0.903.171.357.3ppm2.22.12.01.91.81.71.61.5Ppm********<-7.385-7.3637.2620.900.95-2.1601.00-1.5561.351.419.4011.3841.635.21Pp7.06.8ppm1.004.0ppm7.3857.3637.2627.0837.0667.0196.9656.8936.862-6.840-6.893-6.862--6.8404.0354.0184.0003.9834.0354.0184.0003.983-2.1601.5561.4191.401-1.384---0.000NMR tube.Assign all peaks that have beenintegrated.Below is a real spectrum of the molecule below, shown taken in CDCl3, in a recently cleaned

Given that, a 1H NMR spectrum of a molecule. We have to assign the integrated peaks.

Below is a real spectrum of the molecule below, shown taken in CDCl3, in a recently cleaned NMR tube. Assign all peaks that have been integrated. 7.385 [9E/ 7.385 7.363 7.262 BO'L 06-0 .066 -7.019 6.965 3.177 7.3 S6.0 7.262 £68-9- ppm AL'S 6.862 6.840 7.0 -6.893 ---6.862 -6.840 097-21 www.gm 2.2 2.1 2.0 1.35 SEO 4.018 ppm 000- E86 E 1.00 SEO STO 4.000 (86 E 4.1 4.0 -1.556 1.9 1.8 1.7 1.6 19.1 -2.160 ppm 1.5 1.556 1.419 1.56 TOD'I T PBC* 1.384 ppm 000 0- 5.21 - ppm

Below is a real spectrum of the molecule below, shown taken in CDCl3, in a recently cleaned NMR tube. Assign all peaks that have been integrated. 7.385 [9E/ 7.385 7.363 7.262 BO'L 06-0 .066 -7.019 6.965 3.177 7.3 S6.0 7.262 £68-9- ppm AL'S 6.862 6.840 7.0 -6.893 ---6.862 -6.840 097-21 www.gm 2.2 2.1 2.0 1.35 SEO 4.018 ppm 000- E86 E 1.00 SEO STO 4.000 (86 E 4.1 4.0 -1.556 1.9 1.8 1.7 1.6 19.1 -2.160 ppm 1.5 1.556 1.419 1.56 TOD'I T PBC* 1.384 ppm 000 0- 5.21 - ppm

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter1: Excel Basics

Section: Chapter Questions

Problem 2P

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A volume of 25.00 mL of the original solution was diluted to a total volume of 100.0 mL and then 10.00 mL of that diluted solution was diluted to a total volume of 15.00 mL to make the sample for analysis. If a student in lab found that the solution for spectroscopic analysis had a concentration of (4.0x10^-5) M, what was the concentration of the original solution, in units of M?
Sample 1 Sample 2 Sample 3 Mass of Erlenmeyer Flask (g) 24.33 24.37 24.44 Mass of Erlenmeyer Flask + Calcium Hydroxide Solution (g) (g)(lime water) 27.22 27.29 27.33 Mass of Calcium Hydroxide Solution (g) 2.89 2.92 2.89 Volume of Ca(OH)2 Density = 1.000 g/mL 2.89 2.92 2.89 Concentration of HCl (M) 0.1 0.1 0.1 Initial HCl Volume in Syringe (mL) 1.00+1.00 1.00+1.00 1.00+1.00 Final HCl Volume in Syringe (mL) .72 .66 .54 Volume of HCl Delivered (mL) 1.28 1.34 1.46 Moles of HCl Delivered Moles of OH- in Sample Moles of Ca2+ in Sample Molar Solubility (M) Calculated Ksp Average Calculated Ksp I am very confused how to solve the blank spots in the table. Everything including and after "Moles of HCl Delivered" confuses me. Please help me figure out how to solve the sections correctly. Also feel free to…
Sample 1 Sample 2 Sample 3 Mass of Erlenmeyer Flask (g) 24.33 24.37 24.44 Mass of Erlenmeyer Flask + Calcium Hydroxide Solution (g) (g)(lime water) 27.22 27.29 27.33 Mass of Calcium Hydroxide Solution (g) 2.89 2.92 2.89 Volume of Ca(OH)2 Density = 1.000 g/mL 2.89 2.92 2.89 Concentration of HCl (M) 0.1 0.1 0.1 Initial HCl Volume in Syringe (mL) 1.00+1.00 1.00+1.00 1.00+1.00 Final HCl Volume in Syringe (mL) .72 .66 .54 Volume of HCl Delivered (mL) 1.28 1.34 1.46 Moles of HCl Delivered Moles of OH- in Sample Moles of Ca2+ in Sample Molar Solubility (M) Calculated Ksp Average Calculated Ksp Hello, I need to know how to actually solve each one because I will need to show my work.
I have an equation and the answer, however im not sure how to do the calculation. Please show how to. Answer is supposed to be 0.20 M m1v1=m2v2 (20mL)V=(13mL)(0.30M) V=0.20 M
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A garage manager must determine the number of metal ball bearings (BBs) in a stock container by mass measurements. He counts out 5 BBs and finds their total mass to be 1.9 g. He also finds the total mass of the stock container and the BBs to be 239.3 g and the mass of an identical, empty stock container to be 115.8 g. The store manager then uses his data to calculate the number of BBs in the stock container: Average mass of one BB = 1.9/5 = 0.4 g Mass of BBs in container = 239.3 g - 115.8 g = 123.50 g Number of BBs in container = 123.50/0.4 g= 300 BBs (a) Evaluate the manager’s calculations with regard to significant digits. If necessary, rewrite any steps, recalculating with the adjusted quantities. For any step that you have to rewrite, explain why the manager’s calculation is in error. (b) Should the manager regard the answer to the calculation in (a) as a perfect measure of the number of ball bearings in the container? (c) How could the manager have changed his procedure to…
Show complete solution(steo by step process if can). Round everything to four decimal places. Show conversion(if any) and observe proper units.
Table 5.5 (data)ObservationsSample Tested Add HCISolid CaCO 3 _______Solid CuSo 4 _______Mixture _______Filtrate _______Solid fromfunnel _______