Below is an extract which describes the mechanism of action of aldolase during the cleavage of fructose 1, 6-bisphosphate to produce dihydroxyacetone phosphate (DHAP) and glyceraldehyde 3-phosphate (GAP). Fill in the missing words to complete the extract. Listed here is the pool of words to select from: abstracts, acidic, amine, covalent, hydroxyl, lysine, nitrogen, Schiff base, tetrahedral, water. Ring opening of F1,6BP occurs to render a linear sugar bisphosphate molecule. A __________ residue attacks the carbonyl carbon of F1,6BP. As the carbonyl Oxygen gets a negative charge, a proton is abstracted from the active site _________ amino acid. A _________ intermediate is produced. The active site basic amino acid residue _________ a proton from the lysine. A carbon- __________ double bond forms, producing a protonated Schiff base. At the same time, a solvent proton combines with the released hydroxyl group from C2 to form ________ and leaves the active site. The second active site basic amino acid residue abstracts a proton from the _________ group on C4 to form a carbonyl, breaking the bond between C3-C4. At the same time, electrons from the ________ double bond relocate to Lys and GAP is formed and released from the active site. A ________ enzyme-enamine intermediate remains and then goes through isomerization, amine reforms and a proton is added to C3, producing another protonated Schiff base. A water molecule hydrolyzes the _________ , producing DHAP, and active site proton exchange with the solution restores the active site.
Below is an extract which describes the mechanism of action of aldolase during the cleavage of fructose 1, 6-bisphosphate to produce dihydroxyacetone phosphate (DHAP) and glyceraldehyde 3-phosphate (GAP).
Fill in the missing words to complete the extract.
Listed here is the pool of words to select from: abstracts, acidic,
Ring opening of F1,6BP occurs to render a linear sugar bisphosphate molecule.
A __________ residue attacks the carbonyl carbon of F1,6BP.
As the carbonyl Oxygen gets a negative charge, a proton is abstracted from the active site _________ amino acid.
A _________ intermediate is produced.
The active site basic amino acid residue _________ a proton from the lysine.
A carbon- __________ double bond forms, producing a protonated Schiff base.
At the same time, a solvent proton combines with the released hydroxyl group from C2 to form ________ and leaves the active site.
The second active site basic amino acid residue abstracts a proton from the _________ group on C4 to form a carbonyl, breaking the bond between C3-C4.
At the same time, electrons from the ________ double bond relocate to Lys and GAP is formed and released from the active site.
A ________ enzyme-enamine intermediate remains and then goes through isomerization, amine reforms and a proton is added to C3, producing another protonated Schiff base.
A water molecule hydrolyzes the _________ , producing DHAP, and active site proton exchange with the solution restores the active site.
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