Binary search is performed on a sorted array of n elements. The search key is not in the array and falls between the elements at positions m and m+1 (where 1 ≤ m

The contents of the array below represent a BST (Binary Search Tree). What would be the contents of the array after 30 is deleted. Briefly explain how 30 would be deleted. Use an X to represent any empty spots in the array. 30 2050 10 25 40 60

The algorithm: –In an array of n elements, go to index [n/2] –If the record there is the one you want, you are done –If the record value there is smaller than your search value, all records less than the current record can be ignored – set your search range of elements to [n/2+1…n] and return to step 1 –Otherwise, set your range of elements to [0…(n/2)-1] and return to step 1 –Repeat this loop until you have 0 elements (record is not found) or record is found Short answer Another approach to the update algorithm is to perform use the delete function for the old value and if it is successful, call the insert function using the new value. Explain in your own words if you think this approach is significantly better, worse, or in the same category as the algorithm discussed in the slides, and why.

There exist sorting algorithms which can sort any list with N elements in O(N log N) time. True False

Write pseudocode for a divide-and-conquer algorithm for finding the position of the largest element in an array of n numbers.