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Second base of codon U C A UUU UCU Phenylalanine UCC UAU UGU U Tyrosine tyr y Cysteine U UUC phe F Serine UAC UGC cys C UUA UCA UGA STOP codon UAA STOP codon UAG Leucine ser A UGG Tryptonphan trp W UUG leu UCG L CUU CCU CAU CGU Histidine CUC ССС САС his H CGC Arginine arg R Leucine Proline CỦA leu L ССА pro P САА Glutamine CGA CUG CG CAG gin o CGG AUU ACU AAU AGU Serine ser s Asparagine Isoleucine ACC Threonine AUC AAC asn N AGC ile | AUA ACA thr T AAA AGA Lysine Methionine AUG met (start codon ACG Arginine arg R AAG lys AGG K. GGU GUU GCU GAU Aspartic acid GAC U GUC GCC Alanine asp D GGC C Glycine gly G Valine GUA val V GCA ala A GAA Glutamic acid GGA A GUG GCG GAG glu E GGG G 8) The bolded "A" nucleotide near the beginning of line 2 is the adenine in the intron that is responsible for forming the lariat during splicing. It is thus part of the consensus splicing motif. A) If this is mutated to G, what are the 5 ribonucleotides following exon 1 in the mature MRNA transcript? 5'- -3' B) Does this mutation result in a frame shift? C) How many amino acids are in the protein encoded by the mRNA following this mutation? amino acids D) Using a codon chart (posted under the Translation module in Moodle), translate the mRNA transcript with the mutation described in 8A into protein, using the single letter amino acid code and no spaces. N terminus- -C terminus Third base of codon O

Second base of codon U C A UUU UCU Phenylalanine UCC UAU UGU U Tyrosine tyr y Cysteine U UUC phe F Serine UAC UGC cys C UUA UCA UGA STOP codon UAA STOP codon UAG Leucine ser A UGG Tryptonphan trp W UUG leu UCG L CUU CCU CAU CGU Histidine CUC ССС САС his H CGC Arginine arg R Leucine Proline CỦA leu L ССА pro P САА Glutamine CGA CUG CG CAG gin o CGG AUU ACU AAU AGU Serine ser s Asparagine Isoleucine ACC Threonine AUC AAC asn N AGC ile | AUA ACA thr T AAA AGA Lysine Methionine AUG met (start codon ACG Arginine arg R AAG lys AGG K. GGU GUU GCU GAU Aspartic acid GAC U GUC GCC Alanine asp D GGC C Glycine gly G Valine GUA val V GCA ala A GAA Glutamic acid GGA A GUG GCG GAG glu E GGG G 8) The bolded "A" nucleotide near the beginning of line 2 is the adenine in the intron that is responsible for forming the lariat during splicing. It is thus part of the consensus splicing motif. A) If this is mutated to G, what are the 5 ribonucleotides following exon 1 in the mature MRNA transcript? 5'- -3' B) Does this mutation result in a frame shift? C) How many amino acids are in the protein encoded by the mRNA following this mutation? amino acids D) Using a codon chart (posted under the Translation module in Moodle), translate the mRNA transcript with the mutation described in 8A into protein, using the single letter amino acid code and no spaces. N terminus- -C terminus Third base of codon O

Human Heredity: Principles and Issues (MindTap Course List)
Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter9: Gene Expression And Gene Regulation
Section: Chapter Questions
Problem 17QP: Given the following mRNA, write the double-stranded DNA segment that served as the template....
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Use the first picture and codon table to answer the following questions.

Second base of codon U C A UUU UCU Phenylalanine UCC UAU UGU U Tyrosine tyr y Cysteine U UUC phe F Serine UAC UGC cys C UUA UCA UGA STOP codon UAA STOP codon UAG Leucine ser A UGG Tryptonphan trp W UUG leu UCG L CUU CCU CAU CGU Histidine CUC ССС САС his H CGC Arginine arg R Leucine Proline CỦA leu L ССА pro P САА Glutamine CGA CUG CG CAG gin o CGG AUU ACU AAU AGU Serine ser s Asparagine Isoleucine ACC Threonine AUC AAC asn N AGC ile | AUA ACA thr T AAA AGA Lysine Methionine AUG met (start codon ACG Arginine arg R AAG lys AGG K. GGU GUU GCU GAU Aspartic acid GAC U GUC GCC Alanine asp D GGC C Glycine gly G Valine GUA val V GCA ala A GAA Glutamic acid GGA A GUG GCG GAG glu E GGG G 8) The bolded "A" nucleotide near the beginning of line 2 is the adenine in the intron that is responsible for forming the lariat during splicing. It is thus part of the consensus splicing motif. A) If this is mutated to G, what are the 5 ribonucleotides following exon 1 in the mature MRNA transcript? 5'- -3' B) Does this mutation result in a frame shift? C) How many amino acids are in the protein encoded by the mRNA following this mutation? amino acids D) Using a codon chart (posted under the Translation module in Moodle), translate the mRNA transcript with the mutation described in 8A into protein, using the single letter amino acid code and no spaces. N terminus- -C terminus Third base of codon O <G First base of codon
Transcribed Image Text:Second base of codon U C A UUU UCU Phenylalanine UCC UAU UGU U Tyrosine tyr y Cysteine U UUC phe F Serine UAC UGC cys C UUA UCA UGA STOP codon UAA STOP codon UAG Leucine ser A UGG Tryptonphan trp W UUG leu UCG L CUU CCU CAU CGU Histidine CUC ССС САС his H CGC Arginine arg R Leucine Proline CỦA leu L ССА pro P САА Glutamine CGA CUG CG CAG gin o CGG AUU ACU AAU AGU Serine ser s Asparagine Isoleucine ACC Threonine AUC AAC asn N AGC ile | AUA ACA thr T AAA AGA Lysine Methionine AUG met (start codon ACG Arginine arg R AAG lys AGG K. GGU GUU GCU GAU Aspartic acid GAC U GUC GCC Alanine asp D GGC C Glycine gly G Valine GUA val V GCA ala A GAA Glutamic acid GGA A GUG GCG GAG glu E GGG G 8) The bolded "A" nucleotide near the beginning of line 2 is the adenine in the intron that is responsible for forming the lariat during splicing. It is thus part of the consensus splicing motif. A) If this is mutated to G, what are the 5 ribonucleotides following exon 1 in the mature MRNA transcript? 5'- -3' B) Does this mutation result in a frame shift? C) How many amino acids are in the protein encoded by the mRNA following this mutation? amino acids D) Using a codon chart (posted under the Translation module in Moodle), translate the mRNA transcript with the mutation described in 8A into protein, using the single letter amino acid code and no spaces. N terminus- -C terminus Third base of codon O <G First base of codon
A. Below is a small 2 exon long gene. The exons are underlined, and the 22 nucleotide long intron is the non- underlined sequence between the exons. TAG, TAA, and TGA are stop codons. 5'-TAGTGTATTGACATGATAGAAGCACTCACTATATTCTGACGTGCGACTATGCGTGGGGTTAGGT ATTGTGCTGACTTTTCTCAGGTGGCCCGTATAGGCTAAGCTGCGCATCGCCGCTAGTCGCTCAGTTCCGC TGGCGGCATTTTAACTTTCTTTAATGAATGCGGGCATATTTAATACGCGCTATGCGCATCGTATGCGAT-3'
Transcribed Image Text:A. Below is a small 2 exon long gene. The exons are underlined, and the 22 nucleotide long intron is the non- underlined sequence between the exons. TAG, TAA, and TGA are stop codons. 5'-TAGTGTATTGACATGATAGAAGCACTCACTATATTCTGACGTGCGACTATGCGTGGGGTTAGGT ATTGTGCTGACTTTTCTCAGGTGGCCCGTATAGGCTAAGCTGCGCATCGCCGCTAGTCGCTCAGTTCCGC TGGCGGCATTTTAACTTTCTTTAATGAATGCGGGCATATTTAATACGCGCTATGCGCATCGTATGCGAT-3'
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