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Q: 13C NMR 200 180 160 140 120 100 80 60 40 20 ppm CDs-02-640 Peak # 6 (рpm)
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In 13 C nmr number of unique carbons are equal to number of signals.
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- A compound of unknown structure gave the following spectroscopic data: Mass spectrum: M+=88.1 IR: 3600 cm-1 1ΗNMR: 1.4 δ (2 H, quartet, J=7 Hz); 1.2 δ (6H, singlet): 1.0 δ (1 H, singlet); 0.9 δ (3 H, triplet, J=7 Hz) 13CNMR: 74, 35, 27, 25 δ (a) Assuming that the compound contains C and H but may or may not contain O, give three possible molecular formulas (b) How many protons (H) does the compound contain? (c) What functional groups(s) does the compound contain? (d) How many carbons does the compound contain? (e) What is the molecular formula of the compound? (f) What is the structure of the compound? (g) Assign peaks in the molecule’s 1HNMR spectrum corresponding to specific protons.3-Methyl-2-butanol has five signals in its 13C NMR spectrum at 17.90, 18.15, 20.00, 35.05, and 72.75 . Why are the two methyl groups attached to C3 nonequivalent? Making a molecular model should be helpful.3-Bromo-1-phenyl-1-propene shows a complex NMR spectrum in which the vinylic proton at C2 is coupled with both the C1 vinylic proton (J = 16 Hz) and the C3 methylene protons (J = 8 Hz). Draw a tree diagram for the C2 proton signal, and account for the fact that a five-line multiplet is observed.
- A 13C NMR spectrum of commercially available 2,4-pentanediol, shows five peaks at 23.3, 23.9, 46.5, 64.8, and 68.1 . Explain.Compound F, a hydrocarbon with M+=96 in its mass spectrum, undergoes reaction with HBr to yield compound G. Propose structures for F and G, whose 13C NMR spectral data are given below. Compound F Broadband-decoupled 13C NMR: 27.6, 29.3, 32.2, 132.4 DEPT-90: 132.4 DEPT-135: positive peak at 132.4 ; negative peaks at 27.6, 29.3, 32.2 Compound G Broadband-decoupled 13C NMR: 25.1, 27.7, 39.9, 56.0 DEPT-90: 56.0 DEPT-135: positive peak at 56.0 ; negative peaks at 25.1, 27.7, 39.9The mass spectrum and 13C NMR spectrum of a hydrocarbon are shown. Propose a structure for this hydrocarbon, and explain the spectral data.
- Propose structures for compounds that fit the following descriptions: (a) A hydrocarbon with seven lines in its 13C NMR spectrum (b) A six-carbon compound with only five lines in its 13C NMR spectrum (c) A four-carbon compound with three lines in its 13C NMR spectrumSketch what you might expect the 1H and 13C NMR spectra of the following compound to look like (green = Cl):For each of the molecules in Problem 16.39, determine how many signals should appear in its 13C NMR spectrum.
- The NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 . The 1H and 13C peaks are also listedbelow. Provide a full analysis of the NMR spectra for compound 1. correct assignment of NMR spectra of both 13C spectra. correct rationalisation of 13C spectrum1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).13C NMR (101 MHz, CDCl3) δ 160.79, 154.09, 143.43, 131.85, 127.87, 124.44, 118.86,116.94, 116.74.Note: There are two carbon peaks in the 13C spectrum that are so close together that they are not differentiable at the resolution in this experiment. you should be able to assign these peaks to one of two carbon atoms in 1.Draw the structure of C10H18O2 which is consistent with the 13C NMR data below. Thepeak appearing at 14 ppm is actually two very close peaks.Determine the most likely structure of a compound with the formula C9H12 if it gave an H NMR spectrum consisting of: A doublet at d 1.25, a septet at d 2.90 and a multiplex at d 7.25