(c) A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown in Fig. 1(c). Assume that the transistor common emitter current gain B = 150 and VBE (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes to Vce (sat). Vcc = 12 V Vo(V) Cutoff Vcc Rc= Ic 14 k2 Vo IB Active VCE + Rp= 80 k2 VBE (on) VCE (sat) = Saturation 0.3V V, 0 VeE (on) X V(V) Fig. 1(c)

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(c) A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown
in Fig. 1(c). Assume that the transistor common emitter current gain B = 150 and
VBE (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes
to VcE (sat).
Vcc = 12 V
Vo(V)
Cutoff
Vcc
Rc =
Ic { 1.4 k2
Vo
+
Active
VCE
+
Rp=
80 kΩ
VBE (on)
Vce (sat) =
Saturation
0.3V
V,
0 Ver(on) X
V(V)
Fig. 1(c)
Transcribed Image Text:(c) A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown in Fig. 1(c). Assume that the transistor common emitter current gain B = 150 and VBE (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes to VcE (sat). Vcc = 12 V Vo(V) Cutoff Vcc Rc = Ic { 1.4 k2 Vo + Active VCE + Rp= 80 kΩ VBE (on) Vce (sat) = Saturation 0.3V V, 0 Ver(on) X V(V) Fig. 1(c)
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