Q2. A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown in Fig. 1(c). Assume that the transistor common emitter current gain B = 120 and VBE (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes to VCE (sat). 9 Vcc = 20 V V(V) Cutoff 1.4 k2 RB= 120 kQ Active V, oww VCE VBE (on) VCE (sat) = 1v Saturation O V (on) X

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Q2. A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown in
Fig. 1(c). Assume that the transistor
VBE (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes to
VeE (sat).
common emitter current gain B
120 and
9 Vcc = 20 V
Cutoff
Re
1.4 k2
RB=
120 kQ
Active
V, oww
VCE
VBE (on)
Vce (sat)
1V
Saturation
0 Veg (on) X
V(V)
Transcribed Image Text:Q2. A common-emitter amplifier circuit and its voltage transfer characteristic curve are shown in Fig. 1(c). Assume that the transistor VBE (on) = 0.7 V. Determine the input voltage at the point X, such that the transistor goes to VeE (sat). common emitter current gain B 120 and 9 Vcc = 20 V Cutoff Re 1.4 k2 RB= 120 kQ Active V, oww VCE VBE (on) Vce (sat) 1V Saturation 0 Veg (on) X V(V)
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