(c) Cl2(g) + KBr(aq) → KCI(aq) + Br2(g) O combination decomposition O displacement molecular equation | Cl2(9) + [ reducing agent | KBr(aq) - KCI(aq) + Br2(g) oxidizing agent total ionic equation | Cl2(g) + K*(aq) + Br "(aq) - K*(aq) + Br2(g) + (be). 1) net ionic equation | Cl2(9) + CI "(aq) + |K*(aq) + Br "(aq) - K+(aq) + Br2(g)
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- To determine , by gravimetric analysis, the concentration of barium ions (Ba2+) in a given solution, 25.00cm3 of it are pipetted into a beaker and an excess of dilute sulphuric acid is added to it. The precipitate then obtained (BaSO4) is filtered, dried and weighed. The mass of the precipitate is found to be 1.167g Calculate the concentration of barium ions in the solution? (only 2 decimal places). _________Mol/LIn the standardization of HCl using pure anhydrous sodium carbonate as the primarystandard for methyl orange as an indicator, 1.0 mL HCl was found to be equivalent to 0.05gof sodium carbonate (MW =106). The normality of HCl is:4) A chemist was employed to analyse a particular lawn fertiliser, and dissolved 15.0g of the sample in water. Excess barium chloride was added to precipitate all the sulphate as barium sulphate according to the equation: Ba2+(ap)+SO42-(aq)-> BaSO4(s) When the precipitate was filtered, dried and weighed it had a mass of 4.67g. What was the percentage by mass of sulphate in the lawn fertiliser?
- The reaction mixture intially contains 4.0 g of ferrous ammonium sulfate hexahydrate, Fe(NH4)2(SO4)2 * 6H2O, and 50mL 1M oxalic acid. Determine the limiting reactant,Theoretical yield of the ferrous oxalate dihydrate, and The per cent yield of the ferrous oxalate dihydrate product.The Bayer process is the formation of aluminum hydroxide from metallic aluminum and sodium hydroxide heated to high temperatures. Al(s)+ 3NaOH(aq) -->Al(OH)3(s) + 3Na A manufacturing chemist observes that two distinctly different solids are present in the solutions after the reaction has come to completion. The chemist collected the following data: data table From the above information, identify the limiting and excess reagent, the supporting evidence, and suggest a method to increase the amount of product produced.balance C6H12O6+CO2+H2O with explanation
- Tartaric acid, H2C4H4O6, is a diprotic acid that naturally occurs in the production of wine. Jose was tasked to find out the acid content in a 100.0 mL wine sample by titrating it with a standardized solution of NaOH. He was able to establish the working concentration of the NaOH solution by using 35.21 mL of it to titrate a primary standard of KHP that weighed 3.001 g. The grams and %w/w of Tartaric acid present in the 100.0 mL wine sample were then determined by titrating a 25.00 mL aliquot using 43.56 mL of the standardized NaOH solution. H2C4H4O6 (aq) + 2NaOH (aq) ↔ Na2C4H4O6 (aq) + 2H2O (l) Assume that the density of the wine sample is 1.000 g/mL MM of KHP = 204.22 g/mol MM of H2C4H4O6 = 150.087 g/mol What is the molar concentration of the prepared NaOH solution?…Malic acid (C4H6O5) is a dicarboxylic acid that naturally occurs in the production of bignay wine. Maria was tasked to find out the acid content in a 200.0 mL wine sample by titrating it with a standardized solution of KOH. He was able to establish the working concentration of the KOH solution by using 39.12 mL of it to titrate a primary standard of KHP that weighed 3.021 g. The grams and %w/w of Malic acid present in the 200.0 mL wine sample were then determined by titrating a 20.00 mL aliquot using 48.95 mL of the standardized KOH solution. C4H6O5 (aq) + 2KOH (aq) ↔ K2C4H4O5 (aq) + 2H2O (l) Assume the density of the wine sample is 1.000 g/mL MM of KHP = 204.22 g/mol MM of C4H6O5 = 134.0874 g/mol ? What is the molar concentration of the prepared KOH solution?…Malic acid (C4H6O5) is a dicarboxylic acid that naturally occurs in the production of bignay wine. Maria was tasked to find out the acid content in a 200.0 mL wine sample by titrating it with a standardized solution of KOH. He was able to establish the working concentration of the KOH solution by using 39.12 mL of it to titrate a primary standard of KHP that weighed 3.021 g. The grams and %w/w of Malic acid present in the 200.0 mL wine sample were then determined by titrating a 20.00 mL aliquot using 48.95 mL of the standardized KOH solution. C4H6O5 (aq) + 2KOH (aq) ↔ K2C4H4O5 (aq) + 2H2O (l) Assume the density of the wine sample is 1.000 g/mL MM of KHP = 204.22 g/mol MM of C4H6O5 = 134.0874 g/mol What is the molar concentration of the prepared KOH solution?…
- Zinc and magnesium react with hydrochloric acid to produce the metal chlorides and hydrogen gas. A 10.00 gram smaple of a mixture of Zn and Mg was with the stoichiometric quanitity of HCl. The reaction mixture was then reacted with 156 mL of 3.00M silver nitrate to produce the maximum quantity of silver chloride. First determine the % magnesium in the mixture- then, if 76.0 mL of HCl was added, what was the molarity of the HCl?3. The concentration of acetylsalicylic acid, C9H8O4, in aspirin tablets is determined by hydrolyzing it to the salicylate ion, C7H5O3-, and de¬termining its concentration spectrofluorometrically. A stock standard solution is prepared by weighing 0.0774 g of salicylic acid, C7H6O3, into a 1-L volumetric flask and diluting to volume. A set of calibration standards is prepared by pipeting 0, 2.00, 4.00, 6.00, 8.00, and 10.00 mL of the stock solution into separate 100-mL volumetric flasks that contain 2.00 mL of 4 M NaOH and diluting to volume. Fluorescence is measured at an emission wavelength of 400 nm using an excitation wavelength of 310 nm with results shown in the following table. (a) Why is the excitation wavelength (310 nm) shorter than the emission wavelength (400 nm)?(b) How is the emission wavelength isolated from the excitation wavelength in a fluorescence instrument?The concentration of arsenic in an insecticide can be determined gravimetrically through its precipitation as MgNH4AsO4. After the formation of the precipitate, it must be ignited for total conversion to Mg2As2O7, which is then cooled and weighed. Considering that a sample of 1,627 g of the insecticide produced 106.5 mg of Mg2As2O7, determine the% (m/m) As2O3 in the insecticide. Given the molar masses: Mg2As2O7 = 310.447 g / mol and As2O3 = 197.841 g / mol