Acidity in water can be neutralized with Ca(OH)2 as shown in the equation below. How many lbs/day of pure Ca(OH)2 are required to neutralize an industrial waste with an acidity equivalent to 290 lbs/day of hydrochloric acid? HCI + Ca(OH)2 = CaCI2 + H2O [Unbalanced] MW of HCI = 36.5 g/mol MW of Ca(OH)2 = 74 g/mol

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Acidity in water can be neutralized with Ca(OH)2 as shown in the equation below. How many lbs/day of pure Ca(OH)2 are required to neutralize an industrial waste with an acidity equivalent to 290 lbs/day of hydrochloric acid?
HCI + Ca(OH)2 = CaCI2 + H2O [Unbalanced]

MW of HCI = 36.5 g/mol
MW of Ca(OH)2 = 74 g/mol 

Urgentttttttt pleaseeeee

 

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