C3H8 + 5 O2 → 3 CO2 + 4 H2O a) If I start with 5 grams of C3H8, what is my theoretical yield of water? Molar mass of C3H8 = 44.01g/mol Molar mass of H2O = 18.02 g/mol b) I got a percent yield of 75% How many grams of water did I make?
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C3H8 + 5 O2 → 3 CO2 + 4 H2O
- a) If I start with 5 grams of C3H8, what is my theoretical yield of water?
Molar mass of C3H8 = 44.01g/mol
Molar mass of H2O = 18.02 g/mol
b) I got a percent yield of 75% How many grams of water did I make?
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