Calculate the concentration (in M) of the complex product formed when Pb²+ was reacted with enough EDTA at pH 3. The pPb of the resulting solution is 4.587. (log Kf = 18; a = 2.1x107 11) Express your answer with 3 decimal places and do not encode the units.
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- Aluminium (III) reacts with the Chelating agent HL to give a complex AlL3 that is readily soluble in CHCl3. A spectrophotometric study shows that when a 1.77 x10-4 M aqueous solution of aluminium was extracted with CHCl3 containing 0.01M HL, the analytical concentration of aluminium at pH 4.5 in the two phases were 1.5 x 10-4 M [Al3+]upper) and 2.73 x10-5 M ([AlL3]lower) . What is the distribution coefficient at pH 4.8.10. Potentiometric methods can be used for end-point detection in EDTA titration of metal ions for which ion electrodes are available 11. Back titrations are useful for determining cations that are able to form stable EDTA complexes. 12. Nitriloacetic acid is an aminopolycarboxylic acid. 13. A ligand that has a single donor group is unidentate such as glycine. 14. Ammonia is a bidentate ligand. 15. The term chelate is derived from a Greek word meaning, toothlike projections25.00 mL 0.01000 M Ni2+ is titrated with 0.01000 M EDTA in a solution buffered topH 5.0. Given that the formation constant for the Ni-EDTA (NiY2–) chelate is4.2 x 1018 and the 4 value at pH 5.0 is 3.54 x 10–7. Explain briefly why EDTA is an important reagent used in complexometrictitrations.
- 3. An antacid tablet, weighing 1.25 g, was dissolved in a 1.0 L volumetric flask to allow for determination of calcium carbonate and magnesium carbonate contents. After preparing the solution, an aliquot of 10.0 ml was transferred to an Erlenmeyer flask containing a buffer solution with pH = 10. This aliquot was then titrated with EDTA 0.0040 mol/L and the average volume spent was 15.01 mL. To measure calcium after precipitation. After the magnesium was fractionated, a second 10.00 mL aliquot of the stock solution was transferred to an Erlenmeyer flask, and the pH of the present solution was adjusted to a value of approximately 13. In EDTA titration, the volume consumed for observation ofthe end point was equal to 13.03 mL. Based on this information,a) Outline the two steps involved, representing the related reactions./5b) Calculate the concentrations of CaCO3 and MgCO3 present in the initialsolution./6c) Calculate the masses of CaCO3 and MgCO3 present in the pellet./6d) Calculate the…25.00 mL 0.01000 M Ni2+ is titrated with 0.01000 M EDTA in a solution buffered to pH 5.0. Given that the formation constant for the Ni-EDTA (NiY2–) chelate is 4.2 x 1018 and the 4 value at pH 5.0 is 3.54 x 10–7 An indicator (Ind) forms a metal-indicator complex with Ni2+ (NiInd), giving aconditional formation constant of 1.00 x 108 at pH 5.0. It is generally assumedthat human eyes can detect about 1 part of one color in 10 parts of another;therefore, the first discernible color change will occur when the [NiInd]:[Ind]ratio changes from 10 to about 0.1.A second calibration standard solution of an iron(III) salicylate complex was prepared in two steps. First, 10.0 mL of a 0.100 M stock solution was added to 90.0 mL of solvent to make 100.0 mL of the first calibration standard solution and, secondly, 80 mL of that first calibration solution plus 20.0 mL of solvent were mixed to make the second calibration standard. What is the concentration of the second calibration standard solution?
- what is the purpose of introducing ammonim sulphate to the mixture when determing the formula of a complex ion using colorimetric methodExplain whether or not it will result in a usable standard solution, and why. (Assume appropriate counterions are chosen that do not interfere with the chemistry or spectroscopy.) For any procedure that does work, what is the molarity of FeSCN+2 complex? 0.500 moles of Fe+3 and 0.00500 moles of SCN-1 in 1.0 L of water.A second calibration standard solution of an iron(III) salicylate complex was prepared in two steps. First, 12.9 mL of a 0.481 M stock solution was diluted with solvent to make 100.0 mL of the first calibration standard solution and, secondly, 86.6 mL of that first calibration solution was diluted to 100 mL to make the second calibration standard. What is the molar concentration of the second calibration standard solution? Report your answer to 3 significant figures.
- A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the Fe3+ and leave excess EDTA in solution. The excess EDTA was then back-titrated, requiring 2.37 mL of 0.04615 M Mg2+. What was the concentration of Fe3+ in the original solution in ppm Fe3+?25.00 mL 0.01000 M Ni2+ is titrated with 0.01000 M EDTA in a solution buffered to pH 5.0. Given that the formation constant for the Ni-EDTA (NiY2–) chelate is 4.2 x 1018 and the 4 value at pH 5.0 is 3.54 x 10–7. What is EDTA?An EDTA solution was allowed to react with Pb²⁺ to produce 0.25 M PbY²⁻, 2.67×10⁻⁸ M Pb²⁺ and an excess of 0.10 M at equilibrium (K = 1.1×10⁸). What will be the α₄ value under these conditions?