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A: pKa = 3.110 ----> option(A)
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A: Ka = 2.51x10-5
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Q: The Kb of C6H5NH3* is 3.98x10-10 What is its Ka? Hide answer choices a A 5.02x10^-5 B) 2.51x10^-5 C…
A: The Kb of C6H5NH3+ is 3.98×10-10 .the Ka value calculation is given below.
Q: Q7 Identify each transition (d-d or LMCT or MLCT) (4.5P) 12-6 [CrC(NH,)s)* 200 400 600 2 (nm) log(e)
A:
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- Calculate ΔSsys° (J/K) for the catalytic hydrogenation of acetylene to ethane: C2H2(g) + H2(g) → C2H4(g) Substance S° (J/K·mol) C2H2(g) 200.8 H2(g) 130.58 C2H4(g) 219.438a, solve the problem correctly please and no need to explain too much.NMR spectroscopy is an extremely important technique in organic chemistry. This technique can tell us the number of atoms in a molecule. A) Explain the number of peaks (why 3 peaks?) and the location of each peak (ppm) of adipic acid.