Calculate the mass of limestone (CACO3) that must be decomposed to produce 475 g of lime (CaO). The equation for the reaction is CACO3 (s)CaO(s) + CO2(g) Mass = %3D Submit Answer Try Another Version 10 item attempts remaining

Q: • Part A Iron(III) oxide reacts with carbon monoxide according to the equation Fe203(s) + 3CO(g) →…

A: To solve this problem we will use the given balanced chemical equations .

Q: 1 pt SIMULATION Limiting Reactants 200 Unbalanced Equations 180 - AGNO, + NaCl → AgCl + NaNO3 160-…

A: The balanced reaction is as follows : Molar mass of FeCl3 =162.2 g/mol Molar mass of NaOH = 40g/mol

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Q: LWR # 1 Apply Stoichiometry A student performed an experiment to find the amount of sodium…

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A: Given :-  4Fe2O3(s) + 20NO2(g) + 22H2O(l) + 5O2(g) → 8Fe(OH)3(s) + 20HNO3(aq), ∆H = -1811.2 (kJ/mol)…

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A: Solution to the question is given below.

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A: Given,  mass of Fe=89.6 g mass of C =2.03 g mass of Cr=1.55 g

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Q: 2. Crs) / Craq.o.35M) -3+ // Cu?aq.o.14M) / Cu(s)

A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: will not be available until you sign in again. View earning Ch 7 HW Normandale Community College -…

A: Since you have posted multiple question, we are entitled to answer the first one only.

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Q: 39-40. Consider the chemical equation below 2 C2H2 +5 02 (MW: C2H2 = 26; 02= 32; CO2 = 44; H20 = 18)…

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A: Given equation is balanced so we can count all oxygen atom  directly

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Q: Activity B: Get the Gizmo ready: • Erase the chemical formulas in each text box. Balancing equations…

A: The explanation is given below-

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Q: FeS2 + O2 Fe203 + SO2 820 g O 220 g O 22.0 g O 20.0 g O 29.0 g Submit Request Answer

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A: GivenMass of methane = 12.0gMolar mass of methane= 16.0gMass of oxygen = 15.2gMolar mass of oxygen…

Q: Problem 8.42

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Q: how many grams of hydrogen are contained in 2.50 x 10^23 molecules of ammonium phosphate  show work

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".