Calculate the number of milliliters of 0.750 M NaOH required to precipitate all of the Cr²+ ions in 130 mL of 0.652 M CrI₂ solution as Cr(OH)2. The equation for the reaction is: CrI₂(aq) + 2NaOH(aq) →→→Cr(OH)₂(s) + 2NaI(aq) mL NaOH

Chemistry: Principles and Reactions
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ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
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Chapter20: Chemistry Of The Metals
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Calculate the number of milliliters of 0.750 M
NaOH required to precipitate all of the Cr2+ ions
in 130 mL of 0.652 M CrI₂ solution as Cr(OH)2.
The equation for the reaction is:
CrI₂(aq) + 2NaOH(aq) →→→→Cr(OH)₂(s) +
2NaI(aq)
mL NaOH
Transcribed Image Text:Calculate the number of milliliters of 0.750 M NaOH required to precipitate all of the Cr2+ ions in 130 mL of 0.652 M CrI₂ solution as Cr(OH)2. The equation for the reaction is: CrI₂(aq) + 2NaOH(aq) →→→→Cr(OH)₂(s) + 2NaI(aq) mL NaOH
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