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Calculate the standard enthalpy of formation of N2O5 at 298 K from the following data (all at 298 K):   2NO(g) + O2(g) ---> 2No2(g), delta H = -114.1 kJ/mol 4NO2(g) + O2(g) ---> 2N2O5(g), delta H = -110.2 kJ/mol N2(g) + O2(g) --> 2NO(g), delta H = +180.5 kJ/mol

Calculate the standard enthalpy of formation of N2O5 at 298 K from the following data (all at 298 K):   2NO(g) + O2(g) ---> 2No2(g), delta H = -114.1 kJ/mol 4NO2(g) + O2(g) ---> 2N2O5(g), delta H = -110.2 kJ/mol N2(g) + O2(g) --> 2NO(g), delta H = +180.5 kJ/mol

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.7: Enthalpy Calculations
Problem 5.10CYU: Calculate the standard enthalpy of combustion for benzene, C6H6. C6H6() + 15/2 O2(g) 6 CO2(g) + 3...
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Calculate the standard enthalpy of formation of N2O5 at 298 K from the following data (all at 298 K):

 

2NO(g) + O2(g) ---> 2No2(g), delta H = -114.1 kJ/mol

4NO2(g) + O2(g) ---> 2N2O5(g), delta H = -110.2 kJ/mol

N2(g) + O2(g) --> 2NO(g), delta H = +180.5 kJ/mol

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