Question
Asked Nov 5, 2019
42 views
fullscreen
check_circle

Expert Answer

Step 1

The provided function is shown below.

help_outline

Image Transcriptionclose

v16x2 3x6- 5 f (x)

fullscreen
Step 2

Part (a) To evaluate the below limits

help_outline

Image Transcriptionclose

/16x2 +3x +6 -5 lim f(x) lim and V16x2 +3x +6 -5 lim f(x) lim x-1

fullscreen
Step 3

Divide the numerator and denominator with x an...

help_outline

Image Transcriptionclose

V16x23x65 V16x2 3x6-5 lim x lim x -1 x 16x2 3x 6 5 x- x = lim x 16+ V16x2 3x 6-5 lim x x lim 1 1 х—1 x v16+0+0-0 1-0 = +4 Similarly evaluating the 2nd limit 6 5 16+ V16x23x6-5 lim 2 = lim 1 x /16+0+0-0 1 0 = +4 +

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Math

Calculus