Carbon dioxide and water react to form methanol and oxygen, like this:2CO2(g) + 4H2O(g) → 2CH3OH(l) + 3O2 (g)At a certain temperature, a chemist finds that a 7.5L reaction vessel containing a mixture of carbon dioxide, water, methanol, and oxygen at equilibrium has the following composition:compoundamountCO23.28gH2O3.86gCH3OH1.51gO22.80gCalculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Question
Asked Sep 26, 2019

Carbon dioxide and water react to form methanol and oxygen, like this:

2CO2(g) + 4H2O(g) → 2CH3OH(l) + 3O2 (g)At a certain temperature, a chemist finds that a 7.5L reaction vessel containing a mixture of carbon dioxide, water, methanol, and oxygen at equilibrium has the following composition:
compound amount
CO2
3.28g
H2O
3.86g
CH3OH
1.51g
O2
2.80g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

check_circleExpert Solution
Step 1

It is given that:

Mass of carbon dioxide (CO2) = 3.28 g

Mass of water (H2O) = 3.86 g

Mass of methanol (CH3OH)= 1.51 g

Mass of oxygen (O2) = 2.80 g

Volume of vessel = 7.5 L

Step 2

Equilibrium constant for a reaction can be expressed in terms of concentration of products to the concentration of reactants raised to some power. It is denoted by Kc. The reaction and equilibrium constant for reaction of 2 moles of carbon dioxide with 4 moles of water to give 2 moles of methanol and 3 moles of oxygen is represented as follows:

2со, + 4H,о -> 2CH, ОН +30,
[сH,онf (о,
К.
[со,f[ноf
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2со, + 4H,о -> 2CH, ОН +30, [сH,онf (о, К. [со,f[ноf

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Step 3

To calculate concentration of a substance number ...

Given mass of Co
Molar mass of CO
co
3.28 g
(1x12.0107+2 15.9994) g/mol
=0.0745 mol
Given mass of H,0
HOMolar mass of H,O
3.86 g
(2x1.0087+1x15.9994) g/mol
0.2142 mol
Given mass of CH OH
Molar mass of CH2OH
CHOH
1.51g
(1x12.0107+4x1.0087+1x15.9994) g/mol
-0.2142 mol
Given mass of 0
o
Molar mass of O
2.80 g
(2x15.9994) g/mol
0.0875 mol
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Given mass of Co Molar mass of CO co 3.28 g (1x12.0107+2 15.9994) g/mol =0.0745 mol Given mass of H,0 HOMolar mass of H,O 3.86 g (2x1.0087+1x15.9994) g/mol 0.2142 mol Given mass of CH OH Molar mass of CH2OH CHOH 1.51g (1x12.0107+4x1.0087+1x15.9994) g/mol -0.2142 mol Given mass of 0 o Molar mass of O 2.80 g (2x15.9994) g/mol 0.0875 mol

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