Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S, (g)+C(s) = CS, (g) K. = 9.40 at 900 K How many grams of CS, (g) can be prepared by heating 11.8 mol S,(g) with excess carbon in a 7.45 L reaction vessel held at 900 K until equilibrium is attained? mass of CS,(g):

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter10: Liquids And Solids
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Problem 59E: Consider a cylinder containing a mixture of liquid carbon dioxide in equilibrium with gaseous carbon...
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University Science Books
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istry 4th Edition
McQuarrie Rock Gallogly
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is
S, (g)+C(s) = CS, (g)
K. = 9.40 at 900 K
How many grams of CS, (g) can be prepared by heating 11.8 mol S,(g) with excess carbon in a 7.45 L reaction vessel held at
900 K until equilibrium is attained?
mass of CS,(g):
Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemsitry
Publisher: University Science
50
T.
CT
MacBook Air
Transcribed Image Text:University Science Books presented by Macmillan Learning istry 4th Edition McQuarrie Rock Gallogly Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S, (g)+C(s) = CS, (g) K. = 9.40 at 900 K How many grams of CS, (g) can be prepared by heating 11.8 mol S,(g) with excess carbon in a 7.45 L reaction vessel held at 900 K until equilibrium is attained? mass of CS,(g): Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemsitry Publisher: University Science 50 T. CT MacBook Air
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