Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S,(g) + C(s) = CS, (g) K. = 9.40 at 900 K How many grams of CS, (g) can be prepared by heating 13.0 mol S,(g) with excess carbon in a 5.70 L reaction vessel held at 900 K until equilibrium is attained? mass of CS,(g): g

Chemistry by OpenStax (2015-05-04)
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Chapter13: Fundamental Equilibrium Concepts
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Problem 12E: Show that the complete chemical equation, the total ionic equation, and the net ionic equation for...
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Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is
S,(g) + C(s) = CS, (g)
K. = 9.40 at 900 K
How many grams of CS, (g) can be prepared by heating 13.0 mol S,(g) with excess carbon in a 5.70 L reaction vessel held
at 900 K until equilibrium is attained?
mass of CS,(g):
Transcribed Image Text:Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S,(g) + C(s) = CS, (g) K. = 9.40 at 900 K How many grams of CS, (g) can be prepared by heating 13.0 mol S,(g) with excess carbon in a 5.70 L reaction vessel held at 900 K until equilibrium is attained? mass of CS,(g):
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