Record the information about the lines you have generated. Calculate the temperature for V = 0: {tV=0 = - intercept / slope} for each set of data. Discuss your observations. Chart 2: Charles Law expe rimentHelium: P = 1 atm3.000intercept: 1.352 Lslope: 0.004948 L/°C. Helium: P 0.845 atmintercept: 1.600 Lslope: 0.005853 L/°C2.000V(L)1,000100200300400500t °CcloseCalculations:For mulaV= O{tv=o=- intercept/slope}

According to Charles law which states that at constant pressure, the volume of the fixed amount of…

Chart 2: Charles Law experment Helium: P = 1 atm 3.000 intercept: 1.352 L slope: 0.004948 L/°C 2.000 Helium: P = 0.845 atm %3D intercept: 1.600 L slope: 0.005853 L/°C V(L) 1.000 100 300 200 t °C 400 500 close Calculations: For mula V= O {tv=o=-intercept/5lope}

Chart 2: Charles Law experment Helium: P = 1 atm 3.000 intercept: 1.352 L slope: 0.004948 L/°C 2.000 Helium: P = 0.845 atm %3D intercept: 1.600 L slope: 0.005853 L/°C V(L) 1.000 100 300 200 t °C 400 500 close Calculations: For mula V= O {tv=o=-intercept/5lope}

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter5: Gases, Liquids, And Solids

Section: Chapter Questions

Problem 5.28P

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Question

Record the information about the lines you have generated. Calculate the temperature for V = 0:
{t_V=0 = - intercept / slope} for each set of data.

Discuss your observations.

Chart 2: Charles Law expe riment
Helium: P = 1 atm
3.000
intercept: 1.352 L
slope: 0.004948 L/°C
. Helium: P 0.845 atm
intercept: 1.600 L
slope: 0.005853 L/°C
2.000
V(L)
1,000
100
200
300
400
500
t °C
close
Calculations:
For mula
V= O
{tv=o=- intercept/slope}

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