Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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### Checkpoint 3.59 #### Problem Statement: Assume the variables `name1` and `name2` reference two different `String` objects, containing different strings. Write code that displays the strings referenced by these variables in alphabetical order. ```java ________ { System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } ``` #### Task: Fill in the blank. #### Incorrect Attempt: An attempt was made to fill in the blank with: ```java + " comes before " + name1 + " alphabetically."); ``` This resulted in an incorrect response, as marked by the red 'X' and the message "Incorrect. Try again." ### Solution Explanation: To correctly display `name1` and `name2` in alphabetical order, you need to compare the two strings using the `compareTo` method of the `String` class. Here is the correct code: ```java if (name1.compareTo(name2) < 0) { System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } ``` ### Detailed Explanation: 1. **String Comparison:** - `name1.compareTo(name2) < 0` checks if `name1` is alphabetically before `name2`. The `compareTo` method returns: - A negative integer if `name1` comes before `name2`. - Zero if `name1` and `name2` are equal. - A positive integer if `name1` comes after `name2`. 2. **If-Else Structure:** - If the condition `name1.compareTo(name2) < 0` is true, `name1` is printed first followed by `name2`. - If the condition is false, `name2` is printed first followed by `name1`. This ensures that the strings are always printed in alphabetical order. Remember to always test the logic with different strings to ensure correctness.
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Transcribed Image Text:### Checkpoint 3.59 #### Problem Statement: Assume the variables `name1` and `name2` reference two different `String` objects, containing different strings. Write code that displays the strings referenced by these variables in alphabetical order. ```java ________ { System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } ``` #### Task: Fill in the blank. #### Incorrect Attempt: An attempt was made to fill in the blank with: ```java + " comes before " + name1 + " alphabetically."); ``` This resulted in an incorrect response, as marked by the red 'X' and the message "Incorrect. Try again." ### Solution Explanation: To correctly display `name1` and `name2` in alphabetical order, you need to compare the two strings using the `compareTo` method of the `String` class. Here is the correct code: ```java if (name1.compareTo(name2) < 0) { System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } ``` ### Detailed Explanation: 1. **String Comparison:** - `name1.compareTo(name2) < 0` checks if `name1` is alphabetically before `name2`. The `compareTo` method returns: - A negative integer if `name1` comes before `name2`. - Zero if `name1` and `name2` are equal. - A positive integer if `name1` comes after `name2`. 2. **If-Else Structure:** - If the condition `name1.compareTo(name2) < 0` is true, `name1` is printed first followed by `name2`. - If the condition is false, `name2` is printed first followed by `name1`. This ensures that the strings are always printed in alphabetical order. Remember to always test the logic with different strings to ensure correctness.
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