[References] A salt whose molar mass is 145.43 g/mol is used to make an aqueous solution that is 45.4 % by mass. How many moles of the salt are present? mol mol How many moles of water are present? What is the mole fraction of the salt in the solution? Try Another Version 1 item attempt remaining Submit Answer
[References] A salt whose molar mass is 145.43 g/mol is used to make an aqueous solution that is 45.4 % by mass. How many moles of the salt are present? mol mol How many moles of water are present? What is the mole fraction of the salt in the solution? Try Another Version 1 item attempt remaining Submit Answer
Chemical Principles in the Laboratory
11th Edition
ISBN:9781305264434
Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Chapter24: The Standardization Of A Basic Solution And The Determination Of The Molar Mass Of An Acid
Section: Chapter Questions
Problem 1ASA
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Given in question that , molar mass of solute is 145.43 g/mol. Also given that mass percentage of solution is 45.4% , it means that if solution has 100 g of total weight the mass of solute is 45.4 g and solvent , water has mass of (100-45.4) = 54.6 g.
Moles of any component can be calculated by using following formula -
Moles = mass /molar mass
While mole fraction of any component can be calculated by using Following formula -
Mole fraction of the component = moles of that component/ total number of moles of all components present in solution
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