chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl (aq), as described by the chemical equation MnO2 (s) + 4 HCl (aq) -> MnCl2 (aq) + 2 H2O (l) + Cl2 (g) How much MnO2 (s) should be added to excess HCl (aq) to abtain 145 mL Cl2 (g) at 25 degrees celsius and 735 Torr? Mass of MnO2 = ? g

Chemistry: The Molecular Science
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Chapter3: Chemical Reactions
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chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl (aq), as described by the chemical equation

MnO(s) + 4 HCl (aq) -> MnCl(aq) + 2 H2O (l) + Cl2 (g)

How much MnO(s) should be added to excess HCl (aq) to abtain 145 mL Cl2 (g) at 25 degrees celsius and 735 Torr?

Mass of MnO= ? g

Expert Solution
Step 1

Given:

Volume = 145 mL = 0.145 L.

Temperature = 25 oC = 298 K

Pressure = 735 torr = 0.9671 atm.

Step 2

Calculation for number of moles:

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