Choose the statements that describe why the isomerization reaction is critical for the subsequent cleavage reaction that results in formation of two three-carbon sugars in the glycolytic pathway. The carbon of a carbonyl group has a partial positive charge and can delocalize electrons to facilitate cleavage of the C-C bond. Without the isomerization reaction, C-1 will be the carbonyl carbon and the C-C cleavage will occur between C-2 and C-3. Breaking a C-C bond is energetically unfavorable and can only proceed if a functional group with electronegative atoms is adjacent to the cleavage site to stabilize the reaction intermediates. To cleave a C-C bond, a nucleophilic carbon attacks the adjacent electrophilic carbon. The isomerization reaction moves the carbonyl group to C-2, thus making it a nucleophile that can attack C-3 to generate two three-carbon sugars. ☐ The partial positive charge on the carbonyl carbon can stabilize the carbon radicals formed by the homolytic cleavage of the C-C bond in the six-carbon sugar. Since the C-C cleavage occurs between C-3 and C-4 of the six-carbon sugar, the carbonyl group needs to be on C-2. Cleavage of a C-C bond in the six-carbon sugar occurs via a decarboxylation reaction that requires a carbonyl group adjacent to cleavage site to stabilize the carbanion intermediate.

Biochemistry
6th Edition
ISBN:9781305577206
Author:Reginald H. Garrett, Charles M. Grisham
Publisher:Reginald H. Garrett, Charles M. Grisham
Chapter18: Glycolysis
Section: Chapter Questions
Problem 14P: Energetic of Fructose-1 ,6-bis P Hydrolysis (Integrates with Chapter 3.) The standard free energy...
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Macmillan Learning
The structures of five of the compounds of glycolysis are given. Without using a reference, arrange them in order from the start
of glycolysis to the end of glycolysis.
Reactant for Step 1
H₂C
Product of Step 3
H-C=O
H-C-OH
H-C- -O-PO
H
Product of Step 5
Answer Bank
HO
CH₂OPO3
CO
2-
C H
HTC OH
H COH
2-
CH₂OPO3
Product of Step 6
0=ç-0-PO,
H-C
OH
HIC-O-PO
H-C=0
H
Product of Step 10
C-OH
но- C-H
H C-OH
H-C-OH
CH₂OH
Transcribed Image Text:Macmillan Learning The structures of five of the compounds of glycolysis are given. Without using a reference, arrange them in order from the start of glycolysis to the end of glycolysis. Reactant for Step 1 H₂C Product of Step 3 H-C=O H-C-OH H-C- -O-PO H Product of Step 5 Answer Bank HO CH₂OPO3 CO 2- C H HTC OH H COH 2- CH₂OPO3 Product of Step 6 0=ç-0-PO, H-C OH HIC-O-PO H-C=0 H Product of Step 10 C-OH но- C-H H C-OH H-C-OH CH₂OH
Macmillan Learning
In the glycolytic pathway, glucose 6-phosphate, a six-carbon sugar, is
isomerized to fructose 6-phosphate. Two steps after the isomerization
reaction, the six-carbon sugar is cleaved to form two
three-carbon sugars.
H-
-OH
H
H-C- -OH
HO
H-C-OH
CH₂OPO
Glucose 6-phosphate
phosphohexose
isomerase
H
H-C-OH
O
HO-C-H
H-C-OH
H-C -OH
CH₂OPO
Fructose 6-phosphate
Choose the statements that describe why the isomerization reaction is critical for the subsequent cleavage reaction that
results in formation of two three-carbon sugars in the glycolytic pathway.
The carbon of a carbonyl group has a partial positive charge and can delocalize electrons to facilitate cleavage of the
C-C bond. Without the isomerization reaction, C-1 will be the carbonyl carbon and the C-C cleavage will occur
between C-2 and C-3.
Breaking a C-C bond is energetically unfavorable and can only proceed if a functional group with electronegative
atoms is adjacent to the cleavage site to stabilize the reaction intermediates.
To cleave a C-C bond, a nucleophilic carbon attacks the adjacent electrophilic carbon. The isomerization reaction
moves the carbonyl group to C-2, thus making it a nucleophile that can attack C-3 to generate two three-carbon sugars.
The partial positive charge on the carbonyl carbon can stabilize the carbon radicals formed by the homolytic cleavage
of the C-C bond in the six-carbon sugar. Since the C-C cleavage occurs between C-3 and C-4 of the six-carbon sugar,
the carbonyl group needs to be on C-2.
Cleavage of a C-C bond in the six-carbon sugar occurs via a decarboxylation reaction that requires a carbonyl group
adjacent to cleavage site to stabilize the carbanion intermediate.
Transcribed Image Text:Macmillan Learning In the glycolytic pathway, glucose 6-phosphate, a six-carbon sugar, is isomerized to fructose 6-phosphate. Two steps after the isomerization reaction, the six-carbon sugar is cleaved to form two three-carbon sugars. H- -OH H H-C- -OH HO H-C-OH CH₂OPO Glucose 6-phosphate phosphohexose isomerase H H-C-OH O HO-C-H H-C-OH H-C -OH CH₂OPO Fructose 6-phosphate Choose the statements that describe why the isomerization reaction is critical for the subsequent cleavage reaction that results in formation of two three-carbon sugars in the glycolytic pathway. The carbon of a carbonyl group has a partial positive charge and can delocalize electrons to facilitate cleavage of the C-C bond. Without the isomerization reaction, C-1 will be the carbonyl carbon and the C-C cleavage will occur between C-2 and C-3. Breaking a C-C bond is energetically unfavorable and can only proceed if a functional group with electronegative atoms is adjacent to the cleavage site to stabilize the reaction intermediates. To cleave a C-C bond, a nucleophilic carbon attacks the adjacent electrophilic carbon. The isomerization reaction moves the carbonyl group to C-2, thus making it a nucleophile that can attack C-3 to generate two three-carbon sugars. The partial positive charge on the carbonyl carbon can stabilize the carbon radicals formed by the homolytic cleavage of the C-C bond in the six-carbon sugar. Since the C-C cleavage occurs between C-3 and C-4 of the six-carbon sugar, the carbonyl group needs to be on C-2. Cleavage of a C-C bond in the six-carbon sugar occurs via a decarboxylation reaction that requires a carbonyl group adjacent to cleavage site to stabilize the carbanion intermediate.
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