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Please answer the question in the screenshot. The language used here is in Java.
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- Gid Write the following method that returns thesmallest element in an ArrayList:public static <E extends Comparable<E>> E min(ArrayList<E> list)..Write the following method that returns thesmallest element in an ArrayList:public static <E extends Comparable<E>> E min(ArrayList<E> list)Magic Index: A magic index in an array A[ 1 .•. n-1] is defined to be an index such that A[ i] i. Given a sorted array of distinct integers, write a method to find a magic index, if one exists, in array A.FOLLOW UPWhat if the values are not distinct?
- Write a java method that finds the minimum of each arrayProblem (class MergeSalary)First, write a Java method merge that takes as parameter a non-empty double array representingemployees’ salaries. The method merges the values of every 2 adjacent elements. put themerged values at the beginning of the array, and put 0 in the remaining positions. Suppose thatthe original array will contain an even number of elements.Second, write two java methods readArray(int[]a) and printArray(int[]a) thatreads/writes the elements of an array passed in parameter from/to the standard input/output.Finally, Use the following main method to test your different methods:public class MergeSalary{ private static Scanner input = new Scanner(System.in); public static void main(String[] args) { double[] salaries = new double[10]; System.out.print("Enter 10 salaries: "); readArray(salaries); merge(salaries); System.out.print("Salaries after merge: "); printArray(salaries); }}DO NOT POST EXISTING ONE: Write a java method called SearchKey that return the indices of the first and the last occurences of an element k in an array.The function should Return [-1,1] in case the element was not found
- URGENT JAVA Write a Java method that takes two 2 dimensional int arrays (a and b) and a 2 dimensional boolean array (c) where all three arrays have the same size. Your method should return an array (result) such that, if a partic- ular element in c is true, then the corresponding (same indexed) element in result must be the multiplication of the the corresponding elements of a and b. If the element in c is false, then the the corresponding element in result must be the negative of multiplication of the the corresponding element in a and b. For example ifa = {{1,2,3},{4,5}},b = {{1,2,1},{0,2}} andc = {{true,false,true},{false,true}}, then the result should be result={{1, -4, 3}{0, 10}}.Given an array, find the next greater element for each element in the array, ifavailable. If not available, print the element itself. The next greater element y for anelement x in the array is the first element that is greater than x and occurs on its rightside. The next greater element of the right most element in an array is the elementitself.Example: Given A = [ 6 8 4 3 9] the next greater element listB = [8 9 9 9 9]Given an ArrayList of integers, return an ArrayList where all the odds are before the evens in the order that they occur. public ArrayList<Integer> solution(ArrayList<Integer> nums) {ArrayList<Integer> finalList = new ArrayList<>();int index = 0;for (int i = 0; i < nums.size(); i++) {if (nums.get(i) % 2 == 1) {finalList.add(index, nums.get(i));index++;} elsefinalList.add(nums.get(i));}return finalList;} This is my failing code. for [1.-3.3] where [1,3,-3] is being returned
- public static void reverseAscendingSubarrays(int[] items) Rearrange the elements of the given array of integers in place (that is, do not create and return a new array) so that the elements of every maximal strictly ascending subarray are reversed. For example, given the array {5, 7, 10, 4, 2, 7, 8, 1, 3}, after executing this method, the elements of the array would be {10, 7, 5, 4, 8, 7, 2, 3, 1}. Given another argument array {5, 4, 3, 2, 1}, the contents of that array would stay as {5, 4, 3, 2, 1} seeing that its each element is a maximal ascending subarray of length one. public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire…code: import java.util.Random;import java.util.ArrayList;import java.util.Scanner;public class WeekendOrders {/*** * This method takes as input the scanner instance created from main and* asks the user for input on the number of orders placed on each of the * days on the long weekend (Saturday, Sunday, and Monday). * Put the number of orders for each day in an array of fixed size* * * @param scnr (an instance of Scanner)* @return an array of int which includes the number of orders* placed on each day, with one day per index of the array*/public static int[] getUserInput(Scanner scnr){// DO NOT MODIFY THIS LINEint[] userInput = new int[3];// TODO: Prompt user for input on number of orders on each day// and store in userInputreturn userInput; }/*** * This method appends all the new orders for the given day onto the * arraylist. It first generates a random int between 0-2 (inclusive).* If the int is 0: it adds "Burger" to the prevOrders list* If the int is 1: it adds "Fries" to the…Given an array, find the next greater element for each element in the array, ifavailable. If not available, print the element itself. The next greater element y for anelement x in the array is the first element that is greater than x and occurs on its rightside. The next greater element of the right most element in an array is the elementitself.Example: Given A = [ 6 8 4 3 9] the next greater element listB = [8 9 9 9 9]. implement in python