Combustion of 25.08 g of a compound containing only carbon, hydrogen, and oxygen produces 48.99 g CO2 and 25.07 g H2O Part A What is the empirical formula of the compound? C21 H26 O12 САН10 02 C8 HO12 СрH5О Submit Request Answer

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A: Moles of butane = 8.84 moles

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A: The given reaction  2N2H4 + N2O4 → 3N2  + 4 H2O The moles of N2H4 =  8.38 moles

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A: Applying concept of limiting reagent and mole concept.

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Q: Question attached

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