Compile and execute the following code with a GCC compiler and write down the output of the code. Explain where those three printed values come from. #include int main() { } unsigned long address = 0x6F477D30; char buf[4]; printf("%d\n", sizeof (address)); buf [0] = address & 0x000000ff; buf [1] = (address & 0x0000ff00) >> 8; printf("0xx\n", buf[0]); buf[1]); printf("0x8x\n", Based on what you understand from #13, what code should be used to make the fourth byte of buf be the high byte of address (6F)? a. buf[3] = address & 0xff000000; b. buf [3] c. buf [3] = d. buf [4] = = (address & 0x00ff0000) >> 16; (address & 0xff000000) >> 24; (address & 0xff000000) >> 32; 4

4 bit 2’s Complement Multiplier INPUT A: 4 bit 2’s Complement numberINPUT B: 4 bit 2’s Complement numberOUTPUT: the product of A x B represented as a 8 bit 2’s Complement number   Do this:Build a 4 Bit UNSIGNED Multiplier as a subcircuit named UnsignedMultiplier use AND gate ,full and half adders for the circuit

Determine the output of the comparator. 0 0 0 1 0 0 0 1 || аЗа2а1а0 b3b2b1b0 4-bit comparator gt It eq 0/1 0/1 0/1

Briefly explain bitwise multiplication

Convert -112 decimal to 8-bit signed binary