Compound A was added to water and determined to be insoluble. Sodium hydroxide was added which formed conjugate base B and the solid dissolved. OH A B a) Sodium hydroxide removes an H from A to form the conjugate base B. Why is B soluble in water, but A is not? b) If HCI is added to neutralize the solution and convert B back to A, what would be observed in terms of solubility?

Chemical Principles in the Laboratory
11th Edition
ISBN:9781305264434
Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Chapter24: The Standardization Of A Basic Solution And The Determination Of The Molar Mass Of An Acid
Section: Chapter Questions
Problem 2ASA: In an acid-base titration, 21.16 mL of an NaOH solution are needed to neutralize 20.04 mL of a...
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Compound A was added to water and determined to be insoluble. Sodium hydroxide was added which formed conjugate base B
and the solid dissolved.
OH
A
B
a) Sodium hydroxide removes an H from A to form the conjugate base B. Why is B soluble in water, but A is not?
b) If HCI is added to neutralize the solution and convert B back to A, what would be observed in terms of solubility?
Transcribed Image Text:Compound A was added to water and determined to be insoluble. Sodium hydroxide was added which formed conjugate base B and the solid dissolved. OH A B a) Sodium hydroxide removes an H from A to form the conjugate base B. Why is B soluble in water, but A is not? b) If HCI is added to neutralize the solution and convert B back to A, what would be observed in terms of solubility?
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