Compute for the moments of inertia and radius of gyration of the shaded area with respect to the x - y axes. y 1 120- 40 * Dimensions in mm 40 30 30 20 20 50 20 -x

International Edition---engineering Mechanics: Statics, 4th Edition
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ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
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Chapter9: Moments And Products Of Inertia Of Areas
Section: Chapter Questions
Problem 9.8P: Using integration, compute the polar moment of inertia about point O for the circular sector. Check...
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2. Locate the centroid of the shaded area
6 in.
3 in
6 in.
Area (A), in2
(6)(3) = 9
(6) (6) = 36
(6)(9) = 27
AT = 72
6 in
Shape
For x
Σαχ
x =
=
AT
x= -1 in
-72 in ³
72 in²
Example
x, in
y, in
Ax, in ³
Ay, in ³
3
= -2
-18
63
3+6=7
-108
108
54
ΣA, = -72
6
3
6
613
||
: 2
612
11
3
(9) = 6
For y
Σαγ
y =
=
AT
y = 4.625 in
333 in ³
72 in²
162
ΣΑ, = 333
Transcribed Image Text:2. Locate the centroid of the shaded area 6 in. 3 in 6 in. Area (A), in2 (6)(3) = 9 (6) (6) = 36 (6)(9) = 27 AT = 72 6 in Shape For x Σαχ x = = AT x= -1 in -72 in ³ 72 in² Example x, in y, in Ax, in ³ Ay, in ³ 3 = -2 -18 63 3+6=7 -108 108 54 ΣA, = -72 6 3 6 613 || : 2 612 11 3 (9) = 6 For y Σαγ y = = AT y = 4.625 in 333 in ³ 72 in² 162 ΣΑ, = 333
Compute for the moments of inertia and radius of gyration of the shaded area with
respect to the x - y axes.
y
1
120
40
*
Dimensions in mm
40
30
-x
30
20 20
50
€20
Transcribed Image Text:Compute for the moments of inertia and radius of gyration of the shaded area with respect to the x - y axes. y 1 120 40 * Dimensions in mm 40 30 -x 30 20 20 50 €20
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