Consider a 64 bit Block Encryption algorithm E. Suppose you have encrypted a 64 would byte message M1, M2, ... M64. Show / explain using diagrammatic forms how decrypt the message using CBC and OFB-16. Use an 8 byte IV: I1, I2, ... Ig. you

A.Given p=25, q=9, and e=7, generate the public key (n,e) and the private key (n,d) using the RSA Key generation algorithm. (Use Excel for computations) b. Given Bob's public key of (85, 7) and private key of (85, 55), show how Alice can encrypt m=3 to send to Bob. Show the ciphertext. c. Given Bob's public key of (85, 7) and private key of (85, 55), show how Bob can decrypt the ciphertext y=2 received from Alice. Show the plaintext. d. Using the fast exponentiation method, determine 530 mod 47. Show your work.

1) Suppose your RSA modulus is n = 221 and your encryption key e = 19, Find the decryption key d. Show your working. Is this possible for large values of n say of the order of 1024 bits? Give your reasons in one or two sentences.

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Use S-DES to encrypt the plaintext block m = 00011010 using the key K = 1011000101. Show your work, labeling the result after each step and circling the final ciphertext c

Alice and Bod have decided to use a symmetric encryption algorithm. They have some assumptions about their messages:- Messages only contain capital letters (i.e. A to Z)- The length of their shared key must be greater than or equal to the length of the plaintext- They assign each letter a number as follows: (A,0), (B,1), (C,2), (D,3),…, (Z,25)Their algorithm combines the key and the message using modular addition. The numerical values of corresponding message and key letters are added together, modulo 26. For example, if the plain text is “HELLO” and the key is “SECRET” then the encrypted message is calculated as following:Since the length of the plaintext is 5, we just need the first 5 letters of the key (i.e. “SECRE”), then for each letter, we should add corresponding letters in both the plaintext and the key modulo 26.Plaintext: H (7) E (4) L (11) L (11) O (14)Key: S (18) E (4) C (2) R (17) E(4)Cipher: Z (25) I (8) N(13) C(2) S (18) Write a program in Python, C/C++ or JavaScript to…

What is the biggest advantage of CBC mode of operation   a. It does not need Initialization Vector (IV) b. A cipher text block depends on all blocks before it c. It does not propagate errors in the cipher text d. It can encrypt in parallel different parts of the messages