Consider the balanced chemical reaction below. Calculate the percent yield for the reaction. MnO: + 4HCI – MNCI: + Cl: + 2H:O NEXT The reaction was started with 1.00 mol of MnO: and 95.0 g of HCI (MW 36.458 g/mol). Set up the table below that represents 100% yield with the given reaction conditions. Ignore the water side product. MnO: 4HCI MnCl: Before (mol) Change (mol) After (mol)

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Consider the balanced chemical reaction below. Calculate the percent yield for the reaction...
MnO2 + 4HOCI → MnCl2 + Cl2 + 2H2O
1
2
3
NEXT
The reaction was started with 1.00 mol of MnO2 and 95.0 g of HCI (MW 36.458 g/mol). Set up the table below that represents 100% yield
with the given reaction conditions. Ignore the water side product.
MnO2
+
4HCI
MnCl2
+
Cl2
Before (mol)
Change (mol)
After (mol)
Transcribed Image Text:Consider the balanced chemical reaction below. Calculate the percent yield for the reaction... MnO2 + 4HOCI → MnCl2 + Cl2 + 2H2O 1 2 3 NEXT The reaction was started with 1.00 mol of MnO2 and 95.0 g of HCI (MW 36.458 g/mol). Set up the table below that represents 100% yield with the given reaction conditions. Ignore the water side product. MnO2 + 4HCI MnCl2 + Cl2 Before (mol) Change (mol) After (mol)
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