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- A 10 N aqueous sulfuric acid solution (300 Tw) is made to react with a 55% aqueous NaOH solution (640Be, heavier than water) to form 135 g of Na2SO4 per J 00 mL NaOH solution. The volume ratio of the acid solution to the base solution is 2: 1. Find: a) the Limiting reactant; excess reactant b) % excess reactant c) Degree or completion and d) % composition by weight of the materials after reaction.For the following table fill in the missing values and calculate the theoretical yield. A + 2B à C moles 0.00242 0.00242 ?_________ MW ?_________ 98.06 164.16 g ?_________ ?__0.00002467_______ ?_________ mL 0.20 d(g/mL) 0.80Report sheet analysis of KCIO3/KCI Unknown substance 1 Mass of empty 400mL beaker 164.93g, Mass of 30mL beaker+test tube 96.181g, Mass of 30mL beaker+test tube+unkown mixture 97.218g, Mass of unkown substance 1 1.037g, Mass of 400mL beaker and water 304.97g, Temperature of O2 20 celsius, Atmospheric pressure 750.1 torr. Mass of water ___, Volume of O2___, Vapor pressure of water ___torr, Partial pressure of O2 (Po2) ___torr, Partial pressure of O2 (Po2) ___atm, Moles of O2 (no2) ___, Moles of KCIO3 in unkown ___, Grams of KCIO3 in known ___, % by mass KCIO3 in unknown ___.
- When two people, A and B, push against each other and A falls it is because FB > FA Is the statement true or false if false write the correct oneButane, C4H10, burns to completion with 110% theoretical air.4.1) What is the actual air-fuel ratio on mass basis.4.2) What is the actual air-fuel ratio on mole basis. 4.3) What is theoretical air-fuel ratio (mass basis)4.4) What is theoretical air-fuel ratio (mole basis) 4.5 Determine the equivalence ratio.You have a lot of paperwork laying around. A ream of stacked paper is 500 sheets and is 2.0 inches thick. Let's say you had a mole of paper. (1 mole of paper = 6.022 x 1023 sheets of paper) and it was all stacked up in 10 stacks of equal height, each containing a tenth of a mole of sheets. The ten stacks sit one on top of the other. How high are they? (Hint: find the height of a stack of containing 0.1 mole of paper. USE DIMENSIONAL ANALYSIS!) Here are are some conversions you might need: 2.54 cm = 1 in; around 9.46 x 1015 meters / light yr and 3.26 light yr / parsec.
- Beaker 0.00200 M Fe(NO3)3, mL 0.00200 M NaSCN, mL total volume, mL 1 3.000 2.000 10.00 2 3.000 3.000 10.00 3 3.000 4.000 10.00 4 3.000 5.000 10.00 5 (blank) 3.000 0.000 10.00 In Solutions 1-4 you are adding successively larger volumes of 0.00200M SCN- to the Fe3+ solution and diluting to 10.00 ml. Calculate the final diluted molarity of SCN- in solution #1 Your answer should have 3 sig figs =A student reacts a sample of Alka-Seltzer (the reactive ingredient is NaHCO3)with hydrochloric acid and obtains the following data (note that the carbondioxide product that was evolved during the reaction was collected andmeasured):PCO2 = 656.7 torr VCO2 = 16.75 mL TCO2 = 27.0 CWhat was the mass (in grams) of the NaHCO3 present in the original Alka-Seltzersample? (Useful constant: R = 0.08206 Latm/molK)a) 0.0494 gb) 0.0474 gc) 0.0615 gd) 0.0923 gA sample of an industrial waste water is analyzed and found to contain 16.5ppb Fe2+. How many grams of iron could be recovered from 1.81×103 kg of this waste water? Answer:_______ grams Fe
- Acetaminophen, a popular drug taken as pain reliever and fever reducer, is produced together with acetic acid from the reaction of 3.05 g 4-aminophenol and 4.1 ml of acetic anhydride. Acetaminophen was extracted at 60% yield. Density of acetic anhydride at 20 C, 1.08 g/ml. Calculate the actual no. of grams of acetaminophen produced. [Determine L.R., E.R.]In a river with a constant flow rate, the factory releases wastewater containing NaCl at a concentration of 200 mmol / L to the river at 20.0 L / s. The Na+ and Cl- concentrations at the downstream observation point were 1.00 mmol / L and 0.800 mmol / L, respectively. What is the river flow Q and Cl- concentration before the inflow of drainage? The river originally contains 0.500 mmol / L of Na+.how to calculate moles of NaHCO3 and moles of CO2 from Mass of NaHCO3= 0.081g Volume of CO2=5ml show steps 10mins