Consider the following claim. Ho : p =10 H : μ > 10 Use the following information: n = 24, X = 12.7, and S = 3 To find the test statistic (Step 2). Note: Round your answer to TWO decimal places. Consider the following claim. Họ : | = 20 TT 00
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- Q1. An anthropologist wants to collect data to determine whether the two different cultural groups that occupy an isolated Pacific Island grow to be different heights. The results of his samples of the heights of adult females are as follows Do these samples constitute enough evidence to reject the null hypothesis that the heights of the two groups the same? Set alpha to .05.given H a: u>85 and P=0.007. do you reject or fail to reject H0 at the 0.01 level of significance?given the hypothesesH0 :S=S0, HA :S̸=S0, which are tested with a test statistic Y . When H0 is true, the test statistic Y ∼ U nif (0, 1), and your observed value is Y = 0.88. Calculate the two-sided p-value.
- The effectiveness of a new bug repellent is tested on 1616 subjects for a 10 hour period. (Assume normally distributed population.) Based on the number and location of the bug bites, the percentage of surface area exposed protected from bites was calculated for each of the subjects. The results were as follows: ?⎯⎯⎯=92x¯=92, ?=13 s=13 The new repellent is considered effective if it provides a percent repellency of at least 9090. Using ?=0.05α=0.05, construct a hypothesis test with null hypothesis ?≤90μ≤90 and alternative hypothesis ?>90μ>90 to determine whether the mean repellency of the new bug repellent is greater than 9090 by computing the following: (a) the degree of freedom (b) the test statistic The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that ?≤90μ≤90. Our results do not provide enough evidence that the new bug repellent is effective. B. We can reject the null hypothesis that ?≤90μ≤90. Our results indicate that…Refer questions to the image - What are the degrees of freedom?(choose from below) 26 25 69 27 - What is the correct decision for this test? (choose from below) -Since p-value > 0.05, do not reject H0 -Since p-value < 0.05, reject H0 -Since p-value > 0.05, reject H0 -Since p-value < 0.05, do not reject H0 - An appropriate conclusion for this test is(choose from below) -The average first pulse rate of female students is significantly higher than 70 -The average first pulse rate of female students is equal to 70 -The average first pulse rate of female students is significantly lower than 70 -The average first pulse rate of female students could be equal to 70For each of the following research questions, state the null and research hypotheses in words and in symbols; then determine the type of the hypothesis test. A national survey reported that children’s mean cholesterol level is 191 mg/dL. An investigator hypothesizes that cholesterol levels in children might be decreased by educating their parents on proper nutrition and exercise. A well-known pain medication is publicized to produce pain relief in 75% of patients within 30 minutes of taking the drug. A new pharmaceutical company claims that they have developed a new drug that produces pain relief in a larger proportion of people within 30 minutes.
- A sample with M=8 has EX=56. How many scores are in the sample?A supplier claims that the true mean electrical resistance of wiring harnesses of a certain model is 30 ohms. A manufacturer that uses this harness wants to test whether this claim is true. Which of the following is the correct pair of hypotheses to use for this hypothesis test? Pick the right answer below by quoting the numbered point. 1. H0:μ=30 and H1:μ≠30 2. H0:μ⩾30 and H1:μ<30 3. H0:μ⩽30 and H1:μ>30 4. H0:μ≠30 and H1:μ=30 5. H0:μ<30 and H1:μ⩾30 6. H0:μ>30 and H1:μ⩽30Consider the following hypothesis test. H0: ? = 100 Ha: ? ≠ 100 A sample of 65 is used. Identify the p-value. Use ? = 0.05. (a) x = 103 and s = 11.5 Find the p-value. (Round your answer to four decimal places.) p-value = (b)x = 95.5 and s = 11.0 Find the p-value. (Round your answer to four decimal places.) p-value = (c) x = 101 and s = 10.5
- The manufacturer of Lakas Papaya cleansing soap claimed that their product was effective in making the facial skin blemish-free of at least 93% of users who tested it for a period of 1 week. In a sample of 350 people who had problems with their facial skin, the soap provided blemish-free skin for 295 people. Which of the following represents the alternative hypothesis for this problem? A. Ha: p = 0.93B. Ha: p < 0.93C. Ha: p > 0.93D. H_a: p ≠ 0.93Use the following summary to answer the items that follow: Students in the sleep treatment group have higher exam scores than those in the general student population, z = 2.78, p < .01 What was the alpha value used for the test? What was the decision for this test?Use the below information to answer the questions attached ; Step 1 event A : student belongs to atleast one club on campusevent B : student participates in team sports on campus P(A) = 0.42P(B) = 0.38P(A∩B) = 0.05 Step 2 (a) P(A|B) = P(A∩B)P(B) = 0.050.38 = 0.1316 (b) P(B|A) = P(A∩B)P(A) = 0.050.42 = 0.1190 (c) P(A∩B) = 0.05 (d) P(A∩B¯) = 1 - P(A∩B) = 1 - 0.05 = 0.95