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- From the results in the table: Question: Is there enough evidence to reject the null hypothesis that the ideal number of children is 2.0 if = 0.05? [Hint: the 2-sided p-value is provided in the cell labeled “Sig. (2-tailed)” and “.000” is equivalent to saying that the p-value is less than 0.001] b) If we were to calculate a 95% confidence interval for mu, would this interval contain the value 2.0?In a test of H0: µ=27 against HA: µ ≠ 27, using α=.05, you get a 95% confidence interval with a lower limit of 26.7 and an upper limit of 28.3. What is your conclusion? a. fail to reject the null hypothesis. b. reject the null hypothesis. c.no enough informationAn investigator has calculated a 95 percent confidence interval for a one-sample t test and found: P{97.0≤μ≤105.0}=0.95. If the investigator wants to test the hull hypothesis H0: μ=100,with α=0.05, the investigator should:
- The test statistic of z=2.42 is obtained when testing the claim that p>0.1. a- identify the hypothesis test as being two-tailed, left-tailed or right tailed b- Find the P value c- Using a significance level of a=0.05, should we reject Ho or should we fail to reject Ho?The test statistic of z=2.19 is obtained when testing the claim that p>0.1. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of α=0.05, should we reject H0 or should we fail to reject H0?For the hypothesis test, H0 : β = β0 vs. H1: β does not equal β1, suppose a valid likelihood ratio test (LRT) can be performed by rejecting the null hypothesis if 2{l(βhat) - l(β0))} > X^2 df, alpha. Which of the following is a valid (1-alpha)100 confidence interval (CI) for the β0? a. {β0: 2{l(βhat) - l(β0))} > Zalpha} b. {β0: 2{l(βhat) - l(β0))} <or equal to Zalpha} c. {β0: 2{l(βhat) - l(β0))} <or equal to X^2df, alpha} d. {β0: 2{l(βhat) - l(β0))} > X^2df, alpha}
- "Trydint" bubble-gum company claims that 7 out of 10 people prefer their gum to "Eklypse". Test their claim at the 99 confidence level.The null and alternative hypothesis in symbols would be one of these: H0:p=0.7H1:p≠0.7 H0:p≥0.7H1:p<0.7 H0:p≤0.7H1:p>0.7 H0:μ≤0.7H1:μ>0.7 H0:μ=0.7H1:μ≠0.7 H0:μ≥0.7H1:μ<0.7 The null hypothesis in words would be one of these: The average of people that prefer Trydint gum is 0.7. The proportion of all people that prefer Trydint gum is less than 0.7. The average of people that prefer Trydint gum is not 0.7. The proportion of all people that prefer Trydint gum is 0.7 The proportion of people in a sample that prefer Trydint gum is not 0.7 The proportion of all people that prefer Trydint gum is greater than 0.7. The proportion of people in a sample that prefers Trydint gum is 0.7. Based on a sample of 330 people, 210 said they prefer "Trydint" gum to "Eklypse".The point estimate is: _______ (to 3 decimals)The 99 % confidence interval is: ____…Why is it necessary to check that np≥5 and nq≥5? A. It is necessary to check that np≥5 and nq≥5 to be certain that the minimum value of the sample size, n, is met. B. It is necessary to check that np≥5 and nq≥5 because, if either of the values are less than 5, the distribution may not be normally distributed, thus zc cannot be used to calculate the confidence interval. C. It is necessary to check that np≥5 and nq≥5 because the confidence intervals estimating the population proportions will overlap if these values are less than 5. D. It is necessary to check that np≥5 and nq≥5 because, if either of the values are less than 5, the tails on either side of the left and right endpoints are not accounted for."Trydint" bubble-gum company claims that 7 out of 10 people prefer their gum to "Eklypse". Test their claim that it is different at the 99 confidence level.The null and alternative hypothesis in symbols would be: H0:μ=0.7H0:μ=0.7H1:μ>0.7H1:μ>0.7 H0:p=0.7H0:p=0.7H1:p>0.7H1:p>0.7 H0:p=0.7H0:p=0.7H1:p≠0.7H1:p≠0.7 H0:μ=0.7H0:μ=0.7H1:μ<0.7H1:μ<0.7 H0:p=0.7H0:p=0.7H1:p<0.7H1:p<0.7 H0:μ=0.7H0:μ=0.7H1:μ≠0.7H1:μ≠0.7 The null hypothesis in words would be: The average of people that prefer Trydint gum is 0.7. The proportion of people in a sample that prefers Trydint gum is 0.7. The proportion of people in a sample that prefer Trydint gum is not 0.7 The average of people that prefer Trydint gum is not 0.7. The proportion of all people that prefer Trydint gum is 0.7 The proportion of all people that prefer Trydint gum is less than 0.7. The proportion of all people that prefer Trydint gum is greater than 0.7. Based on a sample of 200 people, 114 said they prefer…
- The test statistic of z=1.30 is obtained when testing the claim that p>0.4. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of α=0.05, should we reject H0 or should we fail to reject H0?A sample of n = 16 scores has a mean of M = 58 with SS = 960. Use the sample to construct the 90% confidence interval for µ. In describing the findings of a 2010 Public ReligionResearch Institute poll, the researchers reported a 3%margin of error at a 95% confidence level. If instead theyhad used a 99% confidence level, their margin of errorwould have been:A) still 3%, because the same sample is used.B) more than 3%, because they reported greaterconfidence.C) less than 3%, because they reported greaterconfidence.D) more than 3%, because this sample is too small.E) less than 3%, because this sample is too small.