Convert the following C code snippet into the corresponding x86 assembly instructions. 1) if(x<=0) { z = 0; } else if(x <= 10000) { z = 1; } else {      z = 2; }

Systems Architecture
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ISBN:9781305080195
Author:Stephen D. Burd
Publisher:Stephen D. Burd
Chapter4: Processor Technology And Architecture
Section: Chapter Questions
Problem 15VE: A(n) ________________ instruction always alters the instruction execution sequence. A(n)...
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Convert the following C code snippet into the corresponding x86 assembly instructions.

1)

if(x<=0)

{

z = 0;

}

else if(x <= 10000)

{

z = 1;

}

else

{     

z = 2;

}

2)

       int n = 5;

       for(int i = 0; i <= 10; i++)

       {

              cout<<n<<” x ”<<i<<” = ”<<n*i<<endl;

}

3)

                int number = 10;

       int result = 1;

       while (number <= 15)

       {

              result = result * number;

              number++;

       }

       cout<<"Resulted Value : "<<result;

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