Copper reacts with nitric acid via the following equation: 3 Cu(s) + 8 HNO3(aq) → 3 Cu(NO3)2 (aq) + 2 NO(g) + 4H₂O(l) What mass of NO can be formed when 27.7 g of Cu reacts with 77.9 g HNO3? g NO

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Chapter3: Calculations With Chemical Formulas And Equaitons
Section: Chapter Questions
Problem 3.128QP: Copper reacts with nitric acid according to the following reaction....
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Copper reacts with nitric acid via the following equation:
3 Cu(s) + 8 HNO3(aq) → 3 Cu(NO3)2 (aq) + 2 NO(g) + 4H₂O(l)
What mass of NO can be formed when 27.7 g of Cu reacts with 77.9 g HNO3?
g NO
Transcribed Image Text:Copper reacts with nitric acid via the following equation: 3 Cu(s) + 8 HNO3(aq) → 3 Cu(NO3)2 (aq) + 2 NO(g) + 4H₂O(l) What mass of NO can be formed when 27.7 g of Cu reacts with 77.9 g HNO3? g NO
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