Counting sighi Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significa mol 7.81 x 0.10 L | mol %3D 5 ? 78.1 mL x 18. mL 704.2 g + 49.18 mL %3D
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- Two students measured the freezing point of a sample of pure benzene. Student A used an ordinary laboratory thermometer calibrated in 0.1 ℃ units. Student B used a thermometer certified by NIST (National Institute of Standards and Technology) and calibrated in 0.01 °C units. Their results were as follows: Student A: 52 °C, 5.7 °C, 5.5 °C, 5.2 °C Student B: 5.48 °C, 5.52 °C, 5.50 °C, 5.54 °C Calculate the average value for A and B and, knowing the freezing point of benzene is 5.50 °C (and using kelvins for temperature), calculate the percent error for each student. Which student has the smaller error?A student checked the accuracy of two standard top-loading balances by testing them with a standard 5.000-g mass. The results were as follows: Balance 1: 4.99 g, 5.04 g, 5.03 g, 5.01 g Balance 2: 4.97 g, 4.99 g, 4.95 g, 4.96 g Calculate the average values for balances 1 and 2 and calculate the percent error for each. Which balance is more accurate?Magnesium chloride is an important coagulant used in the preparation of tofu from soy milk. Its solubility in water at 20C is 54.6 g/100 g. At 80C, its solubility is 66.1 g/100 g. A mixture is made up of 16.2 g of magnesium chloride and 38.2 g of water at 20C. (a) Is the mixture homogeneous? If it is, how many more grams of magnesium chloride are required to make a saturated solution? If the mixture is not homogeneous, how many grams of magnesium chloride are undissolved? (b) How many more grams of magnesium chloride are needed to make a saturated solution at 80C?
- Some farmers use ammonia, NHS, as a fertilizer. This ammonia is stored in liquid form. Use the particulate perspective to show the transition from liquid ammonia to gaseous ammonia.Specific gravity is a physical property. Beakers hold three clear, colorless liquids A, B, and C. The values of the specific gravities of the liquids are measured and then listed in the Before freezing column. The beakers are placed in a freezer until a solid crust forms across the surface of each. The beakers are placed in a freezer until a solid crust forms across the surface of each. The crusts are removed, and the liquids are warmed to room temperature. Their specific gravities are measured again, and then their values are listed in the After Freezing column. Which beakers contains a pure substance, and which contain a mixture? Explain your reasoningAn experiment was performed to look at how density changes when t he ratio of water and ethanol was changed. The following data was obtained: % Mass Ethano1.00 2.50 3.50 4.00 6.00 7.50 9.50 Density, g/mL0.9963 0.9936 0.9918 0.9910 0.9878 0.9855 0.9826 Use Excel or a similar spreadsheet program to plot these six data points and answer the following questions . a.What is the independent variable? b.What is the dependent variable? c.What is the equation of the best-‐fit line? d.What is the value of the coefficient of determination? e. According to the best-‐fit line, what should the density of pure water be (i.e. what is the density when % mass ethanol = 0.00)?
- Table 2.3 Unit PrefixesPrefix Abbreviation Scientific Notation Examplegiga− G x 1,000,000,000 = x 10+9 1 GB = 10+9 bytesmega− M x 1,000,000 = x 10+6 1 MB = 10+6 byteskilo− k x 1000 = x 10+3 1 kg = 1000 g or 1 g = 10−3 kgdeci− d x 0.1 = x 10−1 1 dm = 0.1 m or 1m = 10−1 dmcenti− c x 0.01 = x 10−2 1 cm = 0.01 m or 1 cm = 10^(−2)mmilli− m x 0.001 = x 10−3 1 mL = 10−3 L or 1000 mL = 1 Lmicro− µ x 0.000001 = x 10−6 1 µm = 10−6 m or 1 m = 10^6 µmnano− n x 0.000000001 = x 10−9 1 ng = 10−9 g or 1 g = 10^9 ngpico− p x 0.000000000001 = x 10−12 1 ps = 10−12 s or 1s =10^12p Use the unit prefix information in Table 2.3 to work the following problems. Express each answer inscientific notation. Use two digits. (a) The distance between Los Angeles and Washington D.C. is 4,297 kilometers. Express this distance in meters, centimeters, and millimeters.(b) The James Webb Space Telescope (JWST) has mirrors coated with gold. The thickness of the gold coating is 100 nanometers. What is the thickness of the…Value Units Number Initial reading of water level (ml) Final reading of water level (ml) Volume (ml) Least count of the balance 0.1 g 1 21.0 24.0 Mass of solid, reading 1 25 g 2 19.0 21.0 Mass of solid, reading 2 24.8 g Average mass of solid 24.75 Least count of the graduated cylinder 1 ml Average volume of solid Density of the solid = mass/volume Standard value of the density of the solid 11.37 gm/cm^3 Percent error in the experimental value of density Probable error in the initial reading of the water level Probable error in the final reading of the water level Probable error in the volume of the solid Probable percent error in the mass of the solid Probable percent error in the volume of the solid Probable percent error in the density of the solid =…Mass of solvent in kilograms. Hint: Mass solvent in grams was 151.5Use the metric definition 1 kg = 1000 g
- Given the following data forMass of test tube, beaker and cyclohexane = 100.17 gMass of test tube and beaker = 84.07 gFreezing point of cyclohexane = 6.59 oCMass of weighing paper + naphthalene =1.080 gMass of weighing paper = 0.928 gFreezing point solution = 5.11oCKf = 20.8oC/mDetermine the followinga. mass of cyclohexane in g (2 decimal places); _____b. mass of naphthalene in g (4 decimal places); _____c. freezing point depression (2 decimal places); _____d. molality of solution (3 significant figures); _____e. moles of naphthalene (3 significant figures); _____f. molar mass of naphthalene, experimentally (3 significant figures); _____g. % error if theoretical molar mass of naphthalene is 128.17 g/ mole, USE ABSOLUTE VALUE (3 significant figure); ____Calculate to the correct number of sig fig and correct unit: (3.26 * 10-3mg)-(7.88 * 10-5mg) (4.02 * 106 dm)+(7.74 * 107dm)1. σ=[(Σd2)/(n-1)]½ n= number of trials d= measured value - mean σ=[(8.50mL-8.74mL)2+(9.72mL-8.74mL)2+(8.00mL-8.74mL)2/(3-1)]½ 2. σ=[(Σd2)/(n-1)]½ n= number of trials d= measured value - mean σ=[(10.69-11.52)2+(11.80-11.52)2+(12.07-11.52)2/(3-1)]½