   Chapter 1, Problem 2RCYU

Chapter
Section
Textbook Problem

A student checked the accuracy of two standard top-loading balances by testing them with a standard 5.000-g mass. The results were as follows:Balance 1: 4.99 g, 5.04 g, 5.03 g, 5.01 gBalance 2: 4.97 g, 4.99 g, 4.95 g, 4.96 gCalculate the average values for balances 1 and 2 and calculate the percent error for each. Which balance is more accurate?

Interpretation Introduction

Interpretation:

The average values and percent error in each case has to be calculated and most accurate balance has to be given.

Concept introduction:

Precision is a measurement indicates how well several determination of the same quantity agree.

Accuracy is the agreement of a measurement with the accepted value of the quantity.

Percent error:

The difference between measured result and the accepted value.

Percenterror=ErrorinmeasurementAcceptedvalue×100%

Error in measurement = Experimentally determined value - Accepted value.

Explanation

Average Value for balance 1 and 2 is calculated as,

Average for balance 1 4.99+ 5.04 + 5.03 + 5.014                                   =  5.0175 gAverage for balance 2 4.97+ 4.99 + 4.95 + 4.964                                   =  4.9675 g.

Hence, the average for balance 1 and 2 are obtained as shown above.

Percent error for balance 1 and 2 is calculated as,

Errorinmeasurement  = 5.0175 g - 5.000 gPercenterrorforbalance 1 = 5.0175 g - 5

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