Course : Data Structure And Algorithms Question : q3//take a single string as input //using this string, you have tocreate multiple queues in which each queue will comprise of sepereate word apperead in input string //at end, you will again create words by dequeuing single letter from all queues //if a queue is empty you will not use that queue and when only one queue is remained. you will create words of lemght equal to no of queues at the start //sample input string = Data Structure and Algo //"queue 1 =Data queue 2=Structure queuue 3 = and queue 4= Algo" //required solution = DSaA atnl trdg ayo ctur e //q3

How do you best explain a data structure that uses a double-linked list?

In python please

Parallel Lists JumpinJive.py >- Terminal Summary 1 # JumpinJava.py - This program looks up and prints t and prices of coffee orders. 2 # Input: In this lab, you use what you have learned about parallel lists to complete a partially completed Interactive Python program. 3 # Output: Name and price of coffee orders or error if add-in is not found 4 The program should either print the name and price for a coffee add-in from the Jumpin' Jive 5 # Declare variables. Coffee Shop or it should print the message "Sorry, we do not carry that.". 6 NUM_ITEMS = 5 # Named constant 8 # Initialized list of add-ins 9 addIns = ["Cream", "Cinnamon", "Chocolate", "Amarett "Whiskey"] Read the problem description carefully before you begin. The data file provided for this lab includes the necessary input statements. You need to write the part of the program that searches for the name of the coffee add-in(s) and either prints the name and price of the add-in or prints 10 the error message if the add-in is not…

This data structure provides a variety of benefits over others, such as a linked list or tree.

Data structure

In C programming ONLY! PLEASE FOLLOW THE INSTRUCTIONS

ORIGINAL Q: Instead of reading in an entire list N1,N2,⋯N1​,N2,⋯​ all at once, some algorithms (depending on the task to be done) can read in only one element at a time and process that single element completely before inputting the next one. This can be a useful technique when the list is very big (e.g., billions of elements) and there might not be enough memory in the computer to store it in its entirety. Write an algorithm that reads in a sequence of values v≥0, one at a time, and computes the average of all the numbers. You should stop the computation when you input a value of V = −1. Do not include this negative value in your computations; it is not a piece of data but only a marker to identify the end of the list. PLEASE MODIFY THE FOLLOWING CODE SO THE USER INPUTS THE NUMBERS ONE BY ONE: ORIGINAL Q: Instead of reading in an entire list N1,N2,⋯N1 ,N2,⋯ all at once, some algorithms (depending on the task to be done) can read in only one element at a time and process that single…

A sequential search of a sorted list can halt when the target is less than a given element in the list. Modify the program to stop when the target becomes less than the current value being compared. In a sorted list, this would indicate that the target is not in the list and searching the remaining values is unnecessary.   -----------------------------------------------------------------------------------   """ File: search.py Project 11.1 """ def sequentialSearch(target, lyst):     """Returns the position of the target item if found,     or -1 otherwise.     The lyst is assumed to be sorted in ascending order."""     position = 0     while position < len(lyst):         if target == lyst[position]:             return position         position += 1     return -1 def main():     """Tests with three lists."""     print(sequentialSearch(3, [0, 1, 2, 3, 4]))     print(sequentialSearch(3, [0, 1, 2]))     # Should stop at second position.     print(sequentialSearch(3, [0, 4, 5, 6])) if…