Create a program in Python that will simulate the BST Inorder Traversal using the given tree: 2 7 o while current is not null 10 15 Then the traversal will be [2,5,7,10,15,20] To solve this, we will follow these steps- • Create two array res and stack, set curr := root Run one infinite loop (20 • push curr into a stack, and set curr := left of curr o when the length of stack=0, then return res o nodepopped element from the stack o insert a value of node into res ocurr:right of curr

Python: Written without libraries method find_ansestors , that takes in an index i and returns all ancestors of node located at index i. What is the time complexity of your function? class ArrayBinaryTree:    def __init__(self):        self._heap = []    def find_ancestors(self, i: int):                if(i==0):                            return;

In java how do you: Delete the lowest/smallest item from the Circular Linked List (provided the list is sorted in ascending order) Reverse a Stack S, using a Queue Q Add the top 2 elements of a Stack S. Return the addition and push the data back in the stack S. How to reverse a Queue using a Stack? How to reverse a Queue using an array?

public ArrayList<Integer> depthFirstTraversal(int[][] adjacency_matrix, int source){//A matrix and a source index is passed in//The traversal will be performed on this matrix and begin from the source index //Stack is created//This stack will be used to process nodes in LIFO order when an unvisited node is foundStack<Integer> stack = new Stack<>();int numNodes = adjacency_matrix.length; //boolean array is created//This array will have a slot for each node//Whenever an unvisited node is visited it's slot in this array will be markedboolean[] visited = new boolean[numNodes]; //This variable will hold the index of the element currently being analyzedint element; //The result of the traversal will be stored in this arraylistArrayList<Integer> traversal = new ArrayList<Integer>(); //Since the source index is passed in it has already been visitedvisited[source] = true; //The source index is added to the queue to continue processing itstack.push(source); while…