PHP Create an associative array that has at least 10 keylelement pairs.а.b. Print out the array , printing out keys and values.d. Look at your array. Come up with some criterion about elements in yourarray, so that about half the elements meet the criterion and half don't. Forexample, if your elements are strings, your criterion might be (<"kangaroo"), or if your elements are numbers, your criterion might be (>89)! Print out only those array elements that meet the criterion. Put thecriterion in a php comment before the code so that I can see it!Sort the array (using a function callyourself!!!) Look up the sort function and the asort functionin www.php.net. Print out the sorted array in table form, printing out keysand values.do not write the sorting code--е.commanunset the fourth element in the sorted array (use the unset function, look itup on www.php.net)g. Print out the reverse sorted array in table form, printing out keys andvalues. Look up rsort and arsort on www.php.neth. Print out the array sorted by KEY value in table form, (look up other sortfunctions) printing out keys and values.use the array_rand function to print out 3 random elements of the array.Remember that every time you refresh your page, these will be differentj. Add 5 new elements to the array and print them out againf.i.

NOTE: Answering only the first 3 subparts as per the guidelines. First, we will create an…

Answered: Create an associative array that has at…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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// Only few methods are mentioned here //Do remaining methods to pass the test methods /*** Removes the specified (num) of the given element from the internal ArrayList of elements. * If num <= 0, don't remove anything. * If num is too large, remove all instances of the given element from the internal ArrayList of elements.* Example:* - For a defined CustomIntegerArrayList containing the integers: 1, 2, 1, 2, 1* - Calling remove(2, 1) would remove the first 2 instances of 1 * - The CustomIntegerArrayList will then contain the integers: 2, 2, 1* - For a defined CustomIntegerArrayList containing the integers: 100, 100, 100 * - Calling remove(4, 100) would remove all instances of 100 * - The CustomIntegerArrayList will then be empty* - For a defined CustomIntegerArrayList containing the integers: 5, 5, 5, 5, 5 * - Calling remove(0, 5) would remove nothing* * @param num number of instances of element to remove * @param element to remove*/ public void remove(int num, int element) {//…
Add a method busiestHour to LogAnalyzer that returns the busiest hour. You can do this by looking through the hourCounts array to find the element with the biggest count. Hint: Do you need to check every element to see if you have found the busiest hour? If so, use a for loop or a for-each loop. Which one is better in this case?
Implement a mergeUniqueValues(arr1, arr2) method. When passed two arrays of strings, it will return an array containing the strings that appear in either or both arrays in sorted order. And the returned array should have no duplicates. For example, if you have two string arrays: arr1: {“Bear”, “Elephant”,”Fox”}arr2: {“Panda”, “Elephant”,”Eagle”} Calling mergeUniqueValues(arr1, arr2) should return a merged and sorted array like: Bear, Eagle, Elephant, Fox, Panda
You are given an int variable k, an int array zipcodeList that has been declared and initialized, an int variable nZips that contains the number of elements in zipcodeList, and a bool variable duplicates. Write some code that assigns true to duplicates if there are two adjacent elements in the array that have the same value, and that assigns false to duplicates otherwise. Use only k, zipcodeList, nZips, and duplicates. duplicates = false; for (k=0; !duplicates && k<nZips-1; k++)if (zipcodeList[k] == zipcodeList[k+1]) duplicates = true;
Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example: Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {
Use the right loop for the right assignment, using all the follow- ing loops: for, while without hasNext(), while with hasNext() and do-while. So I cannot use array. it has to be done in java.
For this exercise, you need to shift all the elements in the array one space to the right (increase the index of the element by 1). The last element will wrap around and become the new first element. For example, given: moveUp({"first", "second", "third", "fourth"}); You would return: {"fourth", "first", "second", "third"} in java
Implement code to shows a linear array where the size is specified in the constructor. Elements are accessed with the [] operator. An error check for index out of range is added.
Please can you tell me if this is true or false? The map(callback [, thisArg]) method returns the index of the first element in the array that passes a test in thecallback function. True False
/** * The constructor has been partially implemented for you. cards is the * ArrayList where you'll be adding all the cards you're given. In addition, * there are two arrays. You don't necessarily need to use them, but using them * will be extremely helpful. * * The rankCounts array is of the same length as the number of Ranks. At * position i of the array, keep a count of the number of cards whose * rank.ordinal() equals i. Repeat the same with Suits for suitCounts. For * example, if your Cards are (Clubs 4, Clubs 10, Spades 2), your suitCounts * array would be {2, 0, 0, 1}. * * @param cards * the list of cards to be added */ public PokerAnalysis(List<Card> cards) { this.cards = new ArrayList<Card>(); this.rankCounts = new int[Rank.values().length]; this.suitCounts = new int[Suit.values().length]; throw new UnsupportedOperationException(); }
# the method take another circular array and returns a linear array containing the common elements between the two circular arrays. def intersection(self, c2): # To Do print("==========Test 10==========") lin_arr9 = [10, 20, 30, 40, 50, None, None, None] c10 = CircularArray(lin_arr9, 5, 5) c10.printFullLinear() # This should print: 40, 50, None, None, None, 10, 20, 30 lin_arr10 = [5, 40, 15, 25, 10, 20, 5, None, None, None, None, None] c11 = CircularArray(lin_arr10, 8, 7) c11.printFullLinear() # This should print: 10, 20, 5, None, None, None, None, None, 5, 40, 15, 25 output = c10.intersection(c11) print(output) # This should print: [10, 20, 40]
In this exercise, you will code a modified version of sequential search from the previous example. Here you should implement a method to do sequential search on an ArrayList of doubles and return the index of the search double, or -1 if it isn’t found using a while loop.

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